Concept explainers
(a) To Determine:
The law of conservation of linear momentum
Answer to Problem 20P
Solution:
To verify, .
Explanation of Solution
Given Info:
The mass of is 1115.7MeV/c2.
The mass of ‘n’ is 939.36 MeV/c2.
The mass of ‘ ’ is 139.6MeV/c2.
Formula Used:
• ‘ ’ is the momentum of .
• ‘ ’is mass of .
• ‘ c’ is velocity of light.
• ‘ ’ is the momentum of ‘n’.
• ‘ ’ is the momentum of .
• ‘ ’is mass of ‘ ’.
• ‘ ’is mass of ‘ ’
• ‘ c’ is velocity of light
Calculation:
Substitute 1115.7MeV/c2 for , to find
(I)
Substitute 939.6 MeV/c2 for ‘n’ and 139.6MeV/c2 for ‘ ’ to find ‘ ’,
(II)
From equation (I)and (II):
(III)
(b) To Determine:
The law of conservation of linear momentum
Answer to Problem 20P
Solution:
To verify, .
Explanation of Solution
Given Info:
The mass of is 1115.7MeV/c2.
The mass of ‘p’ is 938.3 MeV/c2.
The mass of is 493.7 MeV/c2.
Formula Used:
• ‘ ’ is the momentum of .
• ‘ ’is mass of .
• ‘ c’ is velocity of light.
• ‘ ’ is the momentum of ‘p’.
• ‘ ’ is the momentum of ‘ ’.
• ‘ ’is mass of ‘p’
• ‘ ’is mass of ‘ ’.
• ‘ c’ is velocity of light
Calculation:
Substitute 1115.7MeV/c2 for , to find
(IV)
Substitute 938.3 MeV/c2 for ‘n’ and 139.6MeV/c2 for to find
(V)
From equation (IV)and (V):
(VI)
Conclusion:
From equation (VI), the equation is not obeying principle of conservation of linear momentum. Therefore, cannot decay to ‘n’ and
(c) To determine:
The law of conservation of linear momentum
Answer to Problem 20P
Solution:
To verify, .
Explanation of Solution
Given Info:
The mass of is 1115.7 MeV/c2.
The mass of ‘ ’ is 139.6 MeV/c2.
The mass of ‘ ’ is 139.6 MeV/c2.
Formula Used:
• ‘ ’ is the momentum of .
• ‘ ’is mass of .
• ‘ c’ is velocity of light.
• ‘ ’ is the momentum of ‘ ’.
• ‘ ’ is the momentum of ‘ ’.
• ‘ ’is mass of ‘ ’
• ‘ ’is mass of ‘ ’.
• ‘ c’ is velocity of light
Calculation:
Substitute 1115.7MeV/c2 for , to find
(VII)
Substitute 139.6 MeV/c2 for ‘ ’ and 139.6MeV/c2 for to find
(VIII)
From equation (VII)and (VIII):
(IX)
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Physics: Principles with Applications
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