Concept explainers
The minimum kinetic energy of the proton (Ep).
Answer to Problem 17P
Solution:
The minimum kinetic energy of the proton (Ep)is 67.5 MeV.
Explanation of Solution
Given Info:
The energy of the proton is 938.3 MeV/c2
Formula Used:
The formula to calculate the energy is,
• E is the energy produce in the reaction.
• c is the velocity of light at free space ().
• is the mass of the proton (938.3MeV/c2)
• is the mass of the (135.0Mev/c2)
The required reaction is
To evaluate the energy of each proton, equate twice of the relativistic proton energy to the sum of the two protons and energy.
So, the kinetic energy of each proton is,
Calculation:
Substitute 938.3MeV/c2 for ‘ ’and 135.0 MeV/c2 for ‘ ’, the total energy producein the reaction is
(I)
Thus, minimum kinetic energy of the proton (Ep)is 67.5 MeV.
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