![Conceptual Physical Science Explorations](https://www.bartleby.com/isbn_cover_images/9780321567918/9780321567918_largeCoverImage.gif)
According to nebular theory, what happens to a nebula as it contracts under the force of gravity?
![Check Mark](/static/check-mark.png)
The effect to a nebula when it contracts under the force of gravity?
Answer to Problem 1TE
When nebula contract under the force of gravity it spins faster and continuous spinning makes it flattens out into solar system.
Explanation of Solution
According to the nebular theory, it is proposed that the solar system is made by the cloud of gas and dust. These clouds are very large with a diameter of a billion kilometre, which is a thousand times larger than the diameter of Neptune.
These clouds collide because of the effect of gravity. This collapse began slowly, but as the particle come closer to each other, the effect of gravity increases and this process accelerate. The gravitational force causes a nebula to contract, as gravity force increases, it took the shape of a sphere. As the nebula contract, it spins faster, with its continuous spinning motion it becames flattened.
Conclusion:
Therefore, when nebula contract under the force of gravity it spins faster and continuous spinning makes it flattens out into solar system.
Chapter 32 Solutions
Conceptual Physical Science Explorations
Additional Science Textbook Solutions
Campbell Biology: Concepts & Connections (9th Edition)
College Physics: A Strategic Approach (3rd Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Microbiology with Diseases by Body System (5th Edition)
Microbiology: An Introduction
Fundamentals of Anatomy & Physiology (11th Edition)
- No chatgpt plsarrow_forwardNo chatgpt plsarrow_forwardCar A starts from rest at t = 0 and travels along a straight road with a constant acceleration of 6 ft/s^2 until it reaches a speed of 60ft/s. Afterwards it maintains the speed. Also, when t = 0, car B located 6000 ft down the road is traveling towards A at a constant speed of 80 ft/s. Determine the distance traveled by Car A when they pass each other.Write the solution using pen and draw the graph if needed.arrow_forward
- In the given circuit the charge on the plates of 1 μF capacitor, when 100 V battery is connected to the terminals A and B, will be 2 μF A 1 µF B 3 µFarrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forward
- The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed. NOT AI PLSarrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardThe velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forward
- Please don't use Chatgpt will upvote and give handwritten solutionarrow_forwardNo chatgpt pls will upvote Already got wrong chatgpt answerarrow_forwardAn electron and a proton are each accelerated through a potential difference of 21.0 million volts. Find the momentum (in MeV/c) and the kinetic energy (in MeV) of each, and compare with the results of using the classical formulas. Momentum (MeV/c) relativistic classical electron proton Kinetic Energy (MeV)arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)