Delmar's Standard Textbook Of Electricity
7th Edition
ISBN: 9781337900348
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 32, Problem 14RQ
To determine
The efficiency of the motor.
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Design a counter to count-up from 2 to 7 using three of
D Flip Flops
(3) 3-Bit Count up (3 to 5) Using D Flip-Flop:
The State Equation of D Flip-Flop:
Q(t+1)=D(t) => Dn=Qn
Present State
D Flip-Flop
Next State
n
Q2p Q1p Q0p
3
0 1
1
1
Q2n Q1n Q0n D2 D1 D0
0 0 1 0 0
4
1
0
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1 0
1
5
1 0
1
0
1
1
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1
D2-Sum(3,4) and don't care X-Sum(0,1,2,6,7)
D1=Sum(5) and don't care X=Sum(0,1,2,6,7)
D0=Sum(4,5) and don't care X=Sum(0,1,2,6,7)
Using K-map to simplify the functions:
D2=Q1+Q0'
D1=Q1'QO
DO=Q1'
XOX
XOX
Q2 10
Q2 01
Q2 1xx
Q0
QO
Qo
D2 Q2
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Q2
D1 Q1
BCD
CK
Q1
DO QF
►CK
Q0
☐ Present State Next State D Flip-Flop
n Q2p Q1p Q0p Q2n Q1n Q0n D2 D1 D0
2 0 1
0
0 1 1 0 1 1
3 0
1
1
1
0
0 1 00
4
1
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1
0
1
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5
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1 1
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D2
D2=Sum(3,4,5), X=Sum(0,1,7)
D1
Q2
1
Q1
1
0
☑
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Qo
D2=Q0+Q1'
✗
0
Q1
Consider the following 4×1 multiplexer with inputs:
w0=2, w1=1, w2=x2' and w3=0
And with switches:
S1 x1 and S0=x0
What is the multiplexer output f as a function of x2, x1
and x0?
I need help adding a capacitor and a Zener diode to my circuit. I’m looking for a simple sketch or diagram showing how to connect them. i want diagram with final circuit after adding the zener diad and capacitor. don't do calclution or anything. thanks
Chapter 32 Solutions
Delmar's Standard Textbook Of Electricity
Ch. 32 - What are the three basic types of three-phase...Ch. 32 - What is the principle of operation of all...Ch. 32 - What is synchronous speed?Ch. 32 - What two factors determine synchronous speed?Ch. 32 - Prob. 5RQCh. 32 - Name three factors that determine the torque...Ch. 32 - Is the synchronous motor an induction motor?Ch. 32 - Prob. 8RQCh. 32 - Why must a synchronous motor never be started when...Ch. 32 - Name three characteristics that make the...
Ch. 32 - What is the function of the field-discharge...Ch. 32 - Why can an induction motor never operate at...Ch. 32 - A squirrel-cage induction motor is operating at...Ch. 32 - Prob. 14RQCh. 32 - Prob. 15RQCh. 32 - Prob. 16RQCh. 32 - Name three factors that determine the amount of...Ch. 32 - Why will the rotor of a wound-rotor motor not turn...Ch. 32 - Why is the starting torque per A of starting...Ch. 32 - When is a synchronous motor a synchronous...Ch. 32 - What determines when a synchronous motor is at...Ch. 32 - How can a synchronous motor be made to have a...Ch. 32 - Is the excitation current of a synchronous motor...Ch. 32 - Prob. 24RQCh. 32 - Prob. 25RQCh. 32 - You are working as a plant electrician. It is your...Ch. 32 - You have been given the task of connecting a...Ch. 32 - You are an electrician working in an industrial...
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- PSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forwardAn AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forward
- Can you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forward
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