Explanation Write the expression for converting temperature from Fahrenheit to Rankine. T = T f + 459.67 °R (I) Here, temperature in Fahrenheit is T f and temperature in Rankine is T . Write the expression for gas constant. R = R ¯ M (II) Here, universal gas constant is R ¯ , Gas constant is R and molecular weight of water is M . Write the expression for mass of gas using ideal gas Equation. m = p V R T (III) Here, mass of the air is m , pressure in atmosphere is p , gas constant is R and temperature is T . Write the expression for weight. W = m g (IV) Here, weight is W and acceleration due to gravity is g . Conclusion: Substitute 80 °F for T f in Equation (I). T = 80 °F + 459.67 = 539.67 °R ≈ 540 °R Refer to Table A-1, “Atomic or Molecular weights and critical Properties of selected Elements and Compounds.” to obtain the molecular weight as 28.97 lb lb ⋅ mol Substitute 1545 ft ⋅ lbf lbmol ⋅ °R for R ¯ and 28.97 lb lb ⋅ mol for M in Equation (II). R = 1545 ( ft ⋅ lbf lb ⋅ mol ⋅ °R ) 28.97 ( lb lb ⋅ mol ) = 53.33 ft ⋅ lbf lb ⋅ °R Substitute 53.33 ft ⋅ lbf lb ⋅ °R for R 1 atm for p and 540 ° R for T in Equation (III). m = ( 1 atm ) ( 8 ft × 9 ft × 12 ft ) ( 53

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ISBN: 9781119391630

Author: MORAN

Publisher: WILEY

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Chapter 3.14, Problem 107P

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Chapter 3.14, Problem 106P

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The mass of the air. The weight of the air.