Explanation Formula used: The inverse Laplace transform of the function F ( s ) is given by L − 1 ( F ) = f ( t ) . The inverse Laplace transform is denoted by L − 1 . The inverse Laplace transform of the function F ( s ) = 2 a s ( s 2 + a 2 ) 2 is given by L − 1 ( 2 a s ( s 2 + a 2 ) 2 ) = t sin a t . The inverse Laplace transform of the function F ( s ) = 2 a 3 ( s 2 + a 2 ) 2 is given by L − 1 ( 2 a 3 ( s 2 + a 2 ) 2 ) = sin a t − a t cos a t . Calculation: The given function is F ( s ) = s + 2 ( s 2 + 9 ) 2 . Using the above formulas, the inverse Laplace transform of the given function can be obtained as follows: L − 1 ( F ) = L − 1 ( s ( s 2 + 9 ) 2 ) + L − 1 (</

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 31.11, Problem 23E

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The inverse Laplace transform of the function F(s)=s+2(s2+9)2.

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Chapter 31.11, Problem 22E

Chapter 31.11, Problem 24E

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Chapter 31 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 31.1 - Show that is a solution of . Is it the general...Ch. 31.1 - Prob. 1E Ch. 31.1 - In Exercises 1 and 2, show that the indicated...Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 4E Ch. 31.1 - In Exercises 3–6, determine whether the given...Ch. 31.1 - Prob. 6E Ch. 31.1 - In Exercises 7–10, show that each function y =...Ch. 31.1 - Prob. 8E Ch. 31.1 - In Exercises 7–10, show that each function y =...

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The inverse Laplace transform of the function F ( s ) = s + 2 ( s 2 + 9 ) 2 .

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The inverse Laplace transform of the function F(s)=s+2(s2+9)2.

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Chapter 31 Solutions