Honeycomb The surface area of a cell in a honeycomb is S = 6 h s + 3 s 2 2 ( 3 − cos θ sin θ ) where h and s are positive constants and θ is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle θ ( π / 6 ≤ θ ≤ π / 2 ) that minimizes the surface area S .
Honeycomb The surface area of a cell in a honeycomb is S = 6 h s + 3 s 2 2 ( 3 − cos θ sin θ ) where h and s are positive constants and θ is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle θ ( π / 6 ≤ θ ≤ π / 2 ) that minimizes the surface area S .
Honeycomb The surface area of a cell in a honeycomb is
S
=
6
h
s
+
3
s
2
2
(
3
−
cos
θ
sin
θ
)
where h and s are positive constants and
θ
is the angle at which the upper faces meet the altitude of the cell (see figure). Find the angle
θ
(
π
/
6
≤
θ
≤
π
/
2
)
that minimizes the surface area S.
Two cables tied together at C are loaded as shown. Given: Q = 130 lb.
8
30°
C
B
Q
3
4
Draw the free-body diagram needed to determine the range of values of P for which both cables remain taut.
Cable AB is 103 ft long and the tension in the cable is 3900 lb.
56 ft
A
50°
20°
B
x
C
Identify the angles 0.0, and 8, that define the direction of force.
1
By
N
2
Match each of the options above to the items below.
142.1°
57.1°
73.3°
3
8.
In the given figure, P = 51 lb .
65°
C
25°
35°
75 lb
P
Determine the corresponding magnitude of the resultant.
The corresponding magnitude of the resultant is|
lb.
Chapter 3 Solutions
WebAssign Printed Access Card for Larson/Edwards' Calculus, 11th Edition, Single-Term
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