EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 31, Problem 49P
To determine
The difference between angles of refraction for red and violet light.
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A beam of light passes through a crystal with index of refraction of 1.65. The crystal has a thickness of 5.00 cm. The light that emerges from the other side is dispersed a distance dcompared to the path the light would take if the refraction didn ́t happen as shown on the figure. a) Determine the dispersion d of the incidence light. b) Determine the time the light takes to pass through the crystal.
10. A light ray of given wavelength, initially in air, strikes a 90°
prism at P (see Fig. 39-53) and is refracted there and at Q to
such an extent that it just grazes the right-hand prism surface
at Q. (a) Determine the index of retraction of the prism for
this wavelength in terms of the angle of incidence , that
gives rise to this situation. (b) Give a numerical upper bound
for the index of refraction of the prism. Show, by ray dia-
grams, what happens if the angle of incidence at P is
(c) slightly greater or (d) slightly less than 0₁.
90
FIGURE 39-53. Problem 10.
..54
Dispersion in a window pane. In
gle e
Fig. 33-54, a beam of white light is incident at an-
50° on a common window pane (shown
in cross section). For the pane's type of glass, the
index of refraction for visible light ranges from
1.524 at the blue end of the spectrum to 1.509 at
the red end. The two sides of the pane are paral-
lel. What is the angular spread of the colors in the
beam (a) when the light enters the pane and
(b) when it emerges from the opposite side?
(Hint: When you look at an object through a window pane, are
the colors the light from the object dispersed as shown in, say,
Fig. 33-20?)
=
Ꮎ
Figure 33-54
Problem 54.
Chapter 31 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 31 - Prob. 1PCh. 31 - Prob. 2PCh. 31 - Prob. 3PCh. 31 - Prob. 4PCh. 31 - Prob. 5PCh. 31 - Prob. 6PCh. 31 - Prob. 7PCh. 31 - Prob. 8PCh. 31 - Prob. 9PCh. 31 - Prob. 10P
Ch. 31 - Prob. 11PCh. 31 - Prob. 12PCh. 31 - Prob. 13PCh. 31 - Prob. 14PCh. 31 - Prob. 15PCh. 31 - Prob. 16PCh. 31 - Prob. 17PCh. 31 - Prob. 18PCh. 31 - Prob. 19PCh. 31 - Prob. 20PCh. 31 - Prob. 21PCh. 31 - Prob. 22PCh. 31 - Prob. 23PCh. 31 - Prob. 24PCh. 31 - Prob. 25PCh. 31 - Prob. 26PCh. 31 - Prob. 27PCh. 31 - Prob. 28PCh. 31 - Prob. 29PCh. 31 - Prob. 30PCh. 31 - Prob. 31PCh. 31 - Prob. 32PCh. 31 - Prob. 33PCh. 31 - Prob. 34PCh. 31 - Prob. 35PCh. 31 - Prob. 36PCh. 31 - Prob. 37PCh. 31 - Prob. 38PCh. 31 - Prob. 39PCh. 31 - Prob. 40PCh. 31 - Prob. 41PCh. 31 - Prob. 42PCh. 31 - Prob. 43PCh. 31 - Prob. 44PCh. 31 - Prob. 45PCh. 31 - Prob. 46PCh. 31 - Prob. 47PCh. 31 - Prob. 48PCh. 31 - Prob. 49PCh. 31 - Prob. 50PCh. 31 - Prob. 51PCh. 31 - Prob. 52PCh. 31 - Prob. 53PCh. 31 - Prob. 54PCh. 31 - Prob. 55PCh. 31 - Prob. 56PCh. 31 - Prob. 57PCh. 31 - Prob. 58PCh. 31 - Prob. 59PCh. 31 - Prob. 60PCh. 31 - Prob. 61PCh. 31 - Prob. 62PCh. 31 - Prob. 63PCh. 31 - Prob. 64PCh. 31 - Prob. 65PCh. 31 - Prob. 66PCh. 31 - Prob. 67PCh. 31 - Prob. 68PCh. 31 - Prob. 69PCh. 31 - Prob. 70PCh. 31 - Prob. 71PCh. 31 - Prob. 72PCh. 31 - Prob. 73PCh. 31 - Prob. 74PCh. 31 - Prob. 75PCh. 31 - Prob. 76PCh. 31 - Prob. 77PCh. 31 - Prob. 78PCh. 31 - Prob. 79PCh. 31 - Prob. 80PCh. 31 - Prob. 81PCh. 31 - Prob. 82PCh. 31 - Prob. 83PCh. 31 - Prob. 84P
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- The index of refraction of diamond is 2.42. By definition, this means that a given wavelength of light travels: O 2.42 times faster in air than it does in diamond O 2.42 times faster in a vacuum than it does in diamond 2.42 times faster in diamond than it does in a vacuum 2.42 times faster in a diamond that it does in airarrow_forwardThe angle of incidence of a light beam in air onto a reflecting surface is continuously variable. The reflected ray is found to be completely polarized when the angle of incidence is 63.0°. (a) What is the index of refraction of the reflecting material? (b) If some of the incident light (at an angle of 63.0°) passes into the material below the surface, what is the angle of refraction? answer in degrees °arrow_forward77 E Rainbow. Figure 33-67 shows a light ray entering and then leaving a falling, spherical raindrop after one internal reflec- tion (see Fig. 33-21a). The final direction of travel is deviated (turned) from the initial direction of travel by angular deviation Bdev- (a) Show that 6sey is Odey = 180° + 20, – 48, where e, is the angle of incidence of the ray on the drop and 0, is the angle of refraction of the ray within the drop. (b) Using Snell's law, substitute for 6, in terms of 6, and the index of refraction n of the water. Then, on a graphing calculator or with a computer graphing package, graph Osey versus 0, for the range of possible 6; values and for n = 1.331 for red light (at one end of the visible spectrum) and n = 1.333 for blue light (at the other end). The red-light curve and the blue-light curve have different minima, which means that there is a different angle of minimum deviation for each color. The light of any given color that leaves the drop at that color's angle of…arrow_forward
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