Chapter 3.1, Problem 3.6BFP

Interpretation Introduction

Interpretation:

The mass of chlorine $\left(\text{Cl}\right)$ in $112\text{ g}$ of ${\text{CCl}}_3\text{F}$ is to be calculated.

Concept introduction:

The molecular formula of a compound tells the number of atoms of each element present in the compound.

The mass fraction of an element in a compound is defined as the ratio of the sum of the masses of all the atoms of that element to that of the mass of one mole of compound.

The formula to calculate the mass fraction of an element A is as follows:

$\text{Mass fraction of A}=\frac{\text{Total mass of A }\left(\text{g}\right)}{\text{Mass of 1 mol compound }\left(\text{g}\right)}$ (1)

The expression to calculate the total mass of an element A in a compound is as follows:

$\text{Total mass of A}=\left(\text{Moles of A in formula}\right)\left(\begin{array}{l}\text{Molar mass of A }\\ \text{in g/mol}\end{array}\right)$ (2)

The multiplication of the mass fraction of element A and mass of the compound gives the mass of element A.

The expression to calculate the mass of an element A in a compound is as follows:

$\text{Mass of A}\left(\text{g}\right)=\left(\text{Mass of compound}\right)\left(\text{Mass fraction of A}\right)$ (3)