Chapter 3.1, Problem 35E

To determine

Histogram to display the distribution of weight and discuss the distribution.

Answer to Problem 35E

The distribution is skewed to right, spread from 0 to 35, with center at 2.5 and without outliers.

Explanation of Solution

Given information:

Data representing population of diamonds formed in a single event deep in the earth:

  

Frequency table:

Find the frequency for each interval that is the number of data values falling within each interval.

The first value of the first interval is 0, having width of 5.

Thus,

The first interval is 0 − <5.

The interval follows

5 − <10, 10 − <15 etc.

The intervals will be established until exactly one interval is allocated to all the data values.

Intervals	Frequency
0 – <5 5 – <10 10 – <15 15 – <20 20 – <25 25 – <30 30 – <35	26 9 5 3 2 2 1

Frequency Histogram:

The bars need to be bounded by interval boundaries and width of each bar should be the same.

Whereas, the height needs to be equal to the frequency.

  

Spread: The weight appears to range from 0.1 to 33.8 in the data set and 0 to 35 in the histogram.

Shape: In the histogram, since the highest bars are to the left along with a tail of smaller balls to the right. Thus, the shape will be skewed to right.

Outliers: Since the histogram does not have gaps, no outliers exist.

Center: Since it is the middle of highest bar, center of the distribution roughly appears to be at 2.5.