Chapter 3, Problem T3.3SPT

To determine

To find: the correlation between temperature and fish activity.

Answer to Problem T3.3SPT

-0.95

Explanation of Solution

Given:

  $r^2=91\%=0.910$

Calculation:

Slope of the least squares regression line is the row “Temperature” and in the column coefficient of the computer output:

  $b_1=-3.2167$

Slope is negative which indicates that there is negative association between the variables and therefore the linear correlation coefficient r is negative.

  $r<0$

So

  $\begin{array}{c}r=-\sqrt{r^2}\\ =-\sqrt{0.910}\\ =-0.95\end{array}$

Hence, the correct option is (e)