Explanation Given data: The patient ingests 3.7 MBq of A 198 u , Half-life of A 198 u is 2.7 days, A 198 u emits 1.4 MeV beta particle, Isotope absorbed and retained in liver is 60%, and Mass of the liver is 1.5 kg. Formula used: Write the expression for radioactivity. R = N × ln ( 2 ) t 1 2 = 0.693 N t 1 2 (1) Here, R is the activity of a radioactive sample, t 1 2 is the half-life, and N is the number of nuclei. Explanation: Consider the conversion factor from days to seconds. 1 d = 60 × 60 × 24 s Convert 2.7 d into seconds by using conversion factor. 2 .7 d = 2.7 ( 1 d ) = 2.7 ( 60 × 60 × 24 s ) = 233 , 280 s Similarly convert the other values. 3.7 MBq = 3.7 × 10 6 Bq { ∵ 1 MBq = 10 6 Bq } 1.4 MeV = 1.4 × 10 6 eV { ∵ 1 MeV = 10 6 eV } Rearrange equation (1) to solve for N . N = t 1 2 R 0.693 (2) Substitute 233280 s for t 1 2 and 3.7 × 10 6 Bq for R in equation (2), N = 233280 s × 3.7 × 10 6 Bq 0.693 = 1.245 × 10 12 Now, The total energy absorbed by the liver is calculated by multiplying the total number of radioactive 198 Au multiplied by the energy of the beta particle emitted and 60%

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Radioactive decay

The emission of energy to produce ionizing radiation is known as radioactive decay. Alpha, beta particles, and gamma rays are examples of ionizing radiation that could be released. Radioactive decay happens in radionuclides, which are imbalanced atoms. T…

Artificial Radioactivity

The radioactivity can be simply referred to as particle emission from nuclei due to the nuclear instability. There are different types of radiation such as alpha, beta and gamma radiation. Along with these there are different types of decay as well.

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Chapter 30, Problem 52P

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The total dose equivalent received by the patient.

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College Physics: A Strategic Approach (3rd Edition)

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