Explanation Formula used: Consider the expression for binding energy. B = ( Z m H + N m n − m atom ) ( 931.49 MeV u ) (1) Here, Z is the Atomic Number, N is the number of neutrons, m H is mass of hydrogen of the atom, m n is the mass of neutron, and m atom is mass of the atom. Consider the expression for energy pr nucleon. Binding energy per nucleon = B A (2) Here, B is the total binding energy and A is the Atomic mass number. Explanation: Substitute 94 for Z , 1.007825 u for m H , 146 for N 1.008665 u for m n and 240.053808 u for m atom in equation (1), B = ( 94 × 1.007825 u + 146 × 1.008665 u − 240.053808 u ) ( 931.49 MeV u ) = 1813.45 MeV Substitute 1813.45 MeV for B and 3 for A in equation (2), ( Binding energy per nucleon ) 240 Pu = 1813

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 30, Problem 13P

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The energy per nucleon of 240Pu and 133Xe .

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Chapter 30, Problem 12P

Chapter 30, Problem 14P

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Set ба ||Axl 49.32 6b 71 Ay 22 Magnitude of A Angle of A 24.04 Angle of -A 22 54 155.96 ° (pos Ax) 204.04 ° (neg Ax) 335.96 ° (pos Ax) ° (neg Ax) 115.77 ° (pos Ax) 295.77 ° (pos Ax) -39 81 208.78 ° (neg Ax) 28.78 ° (neg Ax)

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College Physics: A Strategic Approach (3rd Edition)

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