Two circular coils of radius R , each with N turns, are perpendicular to a common axis. The coil centers are a distance R apart. Each coil carries a steady current I in the same direction as shown in Figure P29.38. (a) Show that the magnetic field on the axis at a distance x from the center of one coil is B = N μ 0 I R 2 2 [ 1 ( R 2 + x 2 ) 3 / 2 + 1 ( 2 R 2 + x 2 − 2 R x ) 3 / 2 ]
Two circular coils of radius R , each with N turns, are perpendicular to a common axis. The coil centers are a distance R apart. Each coil carries a steady current I in the same direction as shown in Figure P29.38. (a) Show that the magnetic field on the axis at a distance x from the center of one coil is B = N μ 0 I R 2 2 [ 1 ( R 2 + x 2 ) 3 / 2 + 1 ( 2 R 2 + x 2 − 2 R x ) 3 / 2 ]
Solution Summary: The author explains the magnetic field on the axis at a distance x from the center of one coil.
Two circular coils of radius R, each with N turns, are perpendicular to a common axis. The coil centers are a distance R apart. Each coil carries a steady current I in the same direction as shown in Figure P29.38. (a) Show that the magnetic field on the axis at a distance x from the center of one coil is
B
=
N
μ
0
I
R
2
2
[
1
(
R
2
+
x
2
)
3
/
2
+
1
(
2
R
2
+
x
2
−
2
R
x
)
3
/
2
]
No chatgpt pls will upvote Already got wrong chatgpt answer
An electron and a proton are each accelerated through a potential difference of 21.0 million volts. Find the momentum (in MeV/c)
and the kinetic energy (in MeV) of each, and compare with the results of using the classical formulas.
Momentum (MeV/c)
relativistic
classical
electron
proton
Kinetic Energy (MeV)
Four capacitors are connected as shown in the figure below. (Let C = 20.0 µF.)
(a) Find the equivalent capacitance between points a and b.
µF
(b) Calculate the charge on each capacitor, taking ΔVab = 14.0 V.
20.0 µF capacitor
µC
6.00 µF capacitor
µC
3.00 µF capacitor
µC
capacitor C
µC
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What is Electromagnetic Induction? | Faraday's Laws and Lenz Law | iKen | iKen Edu | iKen App; Author: Iken Edu;https://www.youtube.com/watch?v=3HyORmBip-w;License: Standard YouTube License, CC-BY