Chapter 30, Problem 23A

To determine

(a)

Measure of the Diameter for (a).

Answer to Problem 23A

The measure of the Diameter is $0.54^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(27\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.54^{″}\end{array}$

Thus, the measure of the Diameter is $0.54^{″}$.

Conclusion:

The measure of the Diameter is $0.54^{″}$.

To determine

(b)

Measure of the Diameter for (b).

Answer to Problem 23A

The measure of the Diameter is $0.42^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(21\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.42^{″}\end{array}$

Thus, the measure of the Diameter is $0.42^{″}$.

Conclusion:

The measure of the Diameter is $0.42^{″}$.

To determine

(c)

Measure of the Diameter for (c).

Answer to Problem 23A

The measure of the Diameter is $1.38^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L=1^{″}+{\left(19\times 0.02\right)}^{\prime \text{}\prime }\\ L=1.38^{″}\end{array}$

Thus, the measure of the Diameter is $1.38^{″}$.

Conclusion:

The measure of the Diameter is $1.38^{″}$.

To determine

(d)

Measure of the Diameter for (d).

Answer to Problem 23A

The measure of the Diameter is $1.18^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L=1^{″}+{\left(9\times 0.02\right)}^{\prime \text{}\prime }\\ L=1.18^{″}\end{array}$

Thus, the measure of the Diameter is $1.18^{″}$.

Conclusion:

The measure of the Diameter is $1.18^{″}$.

To determine

(e)

Measure of the Diameter for (e).

Answer to Problem 23A

The measure of the Diameter is $0.34^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(17\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.34^{″}\end{array}$

Thus, the measure of the Diameter is $0.34^{″}$.

Conclusion:

The measure of the Diameter is $0.34^{″}$.

To determine

(f)

Measure of the Diameter for (f).

Answer to Problem 23A

The measure of the Diameter is $0.28^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(14\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.28^{″}\end{array}$

Thus, the measure of the Diameter is $0.28^{″}$.

Conclusion:

The measure of the Diameter is $0.28^{″}$.

To determine

(g)

Measure of the Diameter for (g).

Answer to Problem 23A

The measure of the Diameter is $1^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(50\times 0.02\right)}^{\prime \text{}\prime }\\ L=1^{″}\end{array}$

Thus, the measure of the Diameter is $1^{″}$.

Conclusion:

The measure of the Diameter is $1^{″}$.

To determine

(h)

Measure of the Diameter for (h).

Answer to Problem 23A

The measure of the Diameter is $0.22^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(11\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.22^{″}\end{array}$

Thus, the measure of the Diameter is $0.22^{″}$.

Conclusion:

The measure of the Diameter is $0.22^{″}$.

To determine

(i)

Measure of the Diameter for (i).

Answer to Problem 23A

The measure of the Diameter is $0.1^{″}$.

Explanation of Solution

Given:

The Hole is given below:

  

Concept used:

Diameter is measured with the help of inch scale.

Calculation:

Attach the inch scale over given Diameter.

  

From the above figure, the Diameter of the Hole can be measured as follows:

  $\begin{array}{l}L={\left(5\times 0.02\right)}^{\prime \text{}\prime }\\ L=0.1^{″}\end{array}$

Thus, the measure of the Diameter is $0.1^{″}$.

Conclusion:

The measure of the Diameter is $0.1^{″}$.