College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 9P
To determine
The amount of force exerted on the body.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A 67.3 kg person is standing inside an elevator. The elevator is traveling from the 1st floor to the 8th floor. As the elevator passes the 7th floor it is traveling at a speed of 3.02 m/s and is decelerating at a rate of 1.39 m/s^2. At that moment, what is the net force acting on the person?
The traveller travels to a planet in a neighboring solar system. It is a long trip, but she somehow manages to maintain her
physical condition by conscientious exercise and diet control. The acceleration due to gravity on this planet is 12.3 m/s². What
is the traveller's mass m' on the planet?
m² =
730.25
kg
A 3.45×103 kg train is stopped at a station. The train must go around a 149 m diameter corner right after it leaves the station. As the train leaves the station it provides a constant forward force of 1.67×103 N. What is the train's acceleration after 5.00 s?
Chapter 3 Solutions
College Physics, Volume 1
Ch. 3.2 - Prob. 3.1CCCh. 3.3 - Prob. 3.2CCCh. 3.4 - Prob. 3.3CCCh. 3.4 - Prob. 3.4CCCh. 3.5 - Prob. 3.5CCCh. 3.6 - Prob. 3.6CCCh. 3.7 - Acceleration of a Skydiver Figure 3.27 shows a...Ch. 3 - Prob. 1QCh. 3 - Prob. 2QCh. 3 - Prob. 3Q
Ch. 3 - Prob. 4QCh. 3 - Prob. 5QCh. 3 - Prob. 6QCh. 3 - Prob. 7QCh. 3 - Prob. 8QCh. 3 - The lower piece of silk in Figure 3.20 is acted on...Ch. 3 - Devise a block-and-tackle arrangement that...Ch. 3 - Prob. 11QCh. 3 - Prob. 12QCh. 3 - Prob. 13QCh. 3 - Prob. 14QCh. 3 - Prob. 15QCh. 3 - Prob. 16QCh. 3 - Prob. 17QCh. 3 - Prob. 18QCh. 3 - Prob. 19QCh. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - A bullet is fired upward with a speed v0 from the...Ch. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Your friends car has broken down, and you...Ch. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - You are given the job of moving a refrigerator of...Ch. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - A hockey puck slides along a rough, icy surface....Ch. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - A crate of mass 55 kg is attached to one end of a...Ch. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - In traction. When a large bone such as the femur...Ch. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Calculate the terminal speed for a pollen grain...Ch. 3 - Prob. 70PCh. 3 - Prob. 71PCh. 3 - Calculate the terminal speed for a baseball. A...Ch. 3 - Prob. 73PCh. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 81PCh. 3 - Prob. 82PCh. 3 - Prob. 83PCh. 3 - Prob. 84PCh. 3 - Prob. 85PCh. 3 - An impish young lad Stands on a bridge 10 m above...Ch. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - Prob. 89PCh. 3 - Prob. 90PCh. 3 - Prob. 91PCh. 3 - Prob. 92PCh. 3 - Prob. 93PCh. 3 - Prob. 94PCh. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 97PCh. 3 - Prob. 98PCh. 3 - Prob. 99P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Two skaters are on an icy pond (no friction). They have masses m1 = 65.0 kg and m2 = 80.0 kg. They are each holding one end of a rope. The heavier skater starts exerting a force of F = 125 N. The rope tautens so that it has a tension T. What is the acceleration of each skater, and what is the tension in the rope?arrow_forwardA 2600 kg car traveling to the north is slowed down uniformly from an initial velocity of 30.5 m/s by a 7670 N braking force acting opposite the car’s motion. (a) What is the car’s velocity after 1.87 s?Answer in units of m/s. (b) How far does the car move during the 1.87 s?Answer in units of m.arrow_forwardA flea jumps by exerting a force of 1.02 x 105N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.20 x 106 N on the flea. Find the direction and magnitude (in m/s2) of the acceleration of the flea if its mass is 6.0 x 107 kg. (Let us assume that Fwind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.) magnitude m/s2 direction ° (measured clockwise from the vertical) Additional Materials O Reading A Tutorialarrow_forward
- A flea jumps by exerting a force of 1.32 x 105 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.16 x 10-6 N on the flea. Find the direction and magnitude (in m/s²) of the acceleration of the flea if its mass is 6.0 x 107 kg. (Let us assume that Fwind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.) magnitude 11.5 x Did you draw a free-body diagram, and identify the forces acting on the flea? Consider the forces acting on the flea during the time it is in contact with the ground. m/s2 85.3 x Review vector components. In which of the four quadrants is the resultant force located?° (measured clockwise from the vertical) direction Tutorial Supporting Materialsarrow_forwardA standard object defined as having a mass of exactly 4.6 kg is given an acceleration of 2.4169 m/s2 when a certain force is applied to it. A second object of unknown mass acquires an acceleration of 1.0268 m/s2 when the same force is applied to it. what is the mass of the second object? Answer in units of kgarrow_forwardA 58.9 kg person is standing inside an elevator. The elevator is moving upward at 3.68 m/s and is decreasing speed at a rate of 1.29 m/s^2. What is the normal force that is acting on the person?arrow_forward
- You walk into an elevator, step onto a scale, and push the "down" button to go directly from the tenth floor to the first floor. You also recall that your normal weight is w = 615 N. If the elevator has an initial acceleration of magnitude 2.45 m/s2, what does the scale read?arrow_forwardA 129 kg crate is sitting at the top of a ramp, which is inclined at an angle of 20 degrees with respect to the horizontal. Someone gives the crate a quick shove to get it moving, after which it slides down the ramp without any further assistance. The coefficient of kinetic friction between the crate and the ramp is ls = 0.23. What is the magnitude of the acceleration (in m/s?) of the crate?arrow_forwardA 1.5-kg mass has an acceleration of (4.0i ^ − 3.0j ^ ) m/s2. Only two forces act on the mass. If one of the forces is (2.0i ^ − 1.4j ^ ) N, what is the magnitude of the other force?arrow_forward
- The velocities of a 3.0-kg object at t = 6.0 s and t = 8.0 s are (3.0i ^ − 6.0j ^ + 4.0k ^ ) m/s and (−2.0i ^ + 4.0k ^ ) m/s , respectively. If the object is moving at constant acceleration, what is the force acting on it?arrow_forwardA rock, in deep space, has a rocket thruster, with negligible mass, attached to it. The rocket causes a force of 3,300[N]. If the rock has a mass of 4.62×104[kg], what is the acceleration experienced by the rock, due to this force alone? Express your answer in terms of m/s2.arrow_forwardYou walk into an elevator, step onto a scale, and push the "down" button to go directly from the tenth floor to the first floor. You also recall that your normal weight is ww = 635 N If the elevator has an initial acceleration of magnitude 2.40 m/s2m/s2, what does the scale read? Express your answer in newtons.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY