College Physics, Volume 1
College Physics, Volume 1
2nd Edition
ISBN: 9781133710271
Author: Giordano
Publisher: Cengage
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Chapter 3, Problem 18P

(a)

To determine

Time took by the barge to reach the bridge.

(a)

Expert Solution
Check Mark

Answer to Problem 18P

The time can be 22.5s_ or 4.9s_.

Explanation of Solution

Write the equation of motion

    S=ut+12at2        (I)

Here S is the distance covered u is the initial velocity, a is the distance covered and t is the time

Substitute the corresponding values for S, u and a in (I) and rearrange to solve the quadratic equation

    40m=(10m/s)t+12(0.73m/s2)t20=(0.365m/s2)t2(10m/s)t+40mt=(10.0m/s)±(10.0 m/s )24(0.365m/s2) (40.0 m)2(0.365m/s2)=22.5 s or 4.9 s

Both the values of time are physically possible.

Conclusion:

The time can be 22.5s_ or 4.9s_.

(b)

To determine

Final velocities for each time.

(b)

Expert Solution
Check Mark

Answer to Problem 18P

For t=4.9s, v=6.4m/s2

For t=22.5s, v=6.4m/s2

Explanation of Solution

Write the equation of motion

    v=u+at        (II)

Conclusion:

Substitute 4.9s for t, 0.73m/s2 for a and 10m/s for u in (II)

    v=(10m/s)+(0.73m/s2)(4.9s)=6.4m/s

Substitute 22.5s4.9s for t, 0.73m/s2 for a and 10m/s for u in (II)

    v=(10m/s)+(0.73m/s2)(22.5s)=6.4m/s

For t=4.9s, v=6.4m/s2

For t=22.5s, v=6.4m/s2

(c)

To determine

Sketch velocity versus time and position versus time graphs.

(c)

Expert Solution
Check Mark

Answer to Problem 18P

The graphs have been drawn.

Explanation of Solution

The short time corresponds to the time it takes the barge to reach the bridge, its velocity is in the positive direction. The longer time corresponds to the total time it takes to reach the bridge.

College Physics, Volume 1, Chapter 3, Problem 18P

Conclusion:

The graphs have been drawn.

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Chapter 3 Solutions

College Physics, Volume 1

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