New Perspectives on HTML and CSS: Brief
6th Edition
ISBN: 9781133387268
Author: Patrick M. Carey
Publisher: Cengage Learning US
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Chapter 3, Problem 8CP1
Program Plan Intro
a) To create a style rule for nav element to float the navigation list on left.
Program Plan Intro
b) To create a style rule for nav element to set left and right padding to 2%.
Program Plan Intro
c) To create a style rule to set the width of navigation list to 30%.
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(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Output:
Exercise 1:====================Go Kean! Have a great semester!
Go Kean!
Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!
(OnlineGDB)
1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
What is the output of the program? Please explain why.
Chapter 3 Solutions
New Perspectives on HTML and CSS: Brief
Ch. 3.1 - Prob. 1QCCh. 3.1 - Prob. 2QCCh. 3.1 - Prob. 3QCCh. 3.1 - Prob. 4QCCh. 3.1 - Prob. 5QCCh. 3.1 - Prob. 6QCCh. 3.1 - Prob. 7QCCh. 3.1 - Prob. 8QCCh. 3.1 - Prob. 9QCCh. 3.2 - Prob. 1QC
Ch. 3.2 - Prob. 2QCCh. 3.2 - Prob. 3QCCh. 3.2 - Prob. 4QCCh. 3.2 - Prob. 5QCCh. 3.2 - Prob. 6QCCh. 3.2 - Prob. 7QCCh. 3.2 - Prob. 8QCCh. 3.2 - Prob. 9QCCh. 3.3 - Prob. 1QCCh. 3.3 - Prob. 2QCCh. 3.3 - Prob. 3QCCh. 3.3 - Prob. 4QCCh. 3.3 - Prob. 5QCCh. 3.3 - Prob. 6QCCh. 3.3 - Prob. 7QCCh. 3 - Prob. 1RACh. 3 - Prob. 2RACh. 3 - Prob. 3RACh. 3 - Prob. 4RACh. 3 - Prob. 5RACh. 3 - Prob. 6RACh. 3 - Prob. 7RACh. 3 - Prob. 8RACh. 3 - Prob. 9RACh. 3 - Prob. 10RACh. 3 - Prob. 11RACh. 3 - Prob. 12RACh. 3 - Prob. 13RACh. 3 - Prob. 14RACh. 3 - Prob. 15RACh. 3 - Prob. 16RACh. 3 - Prob. 1CP1Ch. 3 - Prob. 2CP1Ch. 3 - Prob. 3CP1Ch. 3 - Prob. 4CP1Ch. 3 - Prob. 5CP1Ch. 3 - Prob. 6CP1Ch. 3 - Prob. 7CP1Ch. 3 - Prob. 8CP1Ch. 3 - Prob. 9CP1Ch. 3 - Prob. 10CP1Ch. 3 - Prob. 11CP1Ch. 3 - Prob. 12CP1Ch. 3 - Prob. 13CP1Ch. 3 - Prob. 14CP1Ch. 3 - Prob. 15CP1Ch. 3 - Prob. 16CP1Ch. 3 - Prob. 17CP1Ch. 3 - Prob. 18CP1Ch. 3 - Prob. 19CP1Ch. 3 - Prob. 20CP1Ch. 3 - Prob. 1CP2Ch. 3 - Prob. 2CP2Ch. 3 - Prob. 3CP2Ch. 3 - Prob. 4CP2Ch. 3 - Prob. 5CP2Ch. 3 - Prob. 6CP2Ch. 3 - Prob. 7CP2Ch. 3 - Prob. 8CP2Ch. 3 - Prob. 9CP2Ch. 3 - Prob. 10CP2Ch. 3 - Prob. 11CP2Ch. 3 - Prob. 12CP2Ch. 3 - Prob. 13CP2Ch. 3 - Prob. 14CP2Ch. 3 - Prob. 15CP2Ch. 3 - Prob. 16CP2Ch. 3 - Prob. 17CP2Ch. 3 - Prob. 18CP2Ch. 3 - Prob. 19CP2Ch. 3 - Prob. 20CP2Ch. 3 - Prob. 1CP3Ch. 3 - Prob. 2CP3Ch. 3 - Prob. 3CP3Ch. 3 - Prob. 4CP3Ch. 3 - Prob. 5CP3Ch. 3 - Prob. 6CP3Ch. 3 - Prob. 7CP3Ch. 3 - Prob. 8CP3Ch. 3 - Prob. 9CP3Ch. 3 - Prob. 10CP3Ch. 3 - Prob. 11CP3Ch. 3 - Prob. 12CP3Ch. 3 - Prob. 13CP3Ch. 3 - Prob. 14CP3Ch. 3 - Prob. 1CP4Ch. 3 - Prob. 2CP4Ch. 3 - Prob. 3CP4Ch. 3 - Prob. 4CP4Ch. 3 - Prob. 5CP4Ch. 3 - Prob. 6CP4
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