Explanation Given data: The initial horizontal velocity component ( v x ) i is 6.7 m s . The initial vertical velocity component ( v y ) i is 6.7 m s . Vertical distance from the ramp to the ground ( y i ) is 1.8 m The ramp is angled at ( θ ) is 40 ° Formula used: Formula for horizontal component of initial velocity as follows. ( v x ) i = v i cos θ (I) Here, v i is the initial velocity, θ is the ramp angle. Substitute 6.7 m s for v i and 40 ° for θ in equation (1). ( v x ) i = 6.7 m s × cos ( 40 ° ) = 5.13 m s Formula for vertical component of initial velocity as follows, ( v y ) i = v i sin θ (2) Substitute 6.7 m s for v i and 40 ° for θ in equation (2). ( v y ) i = ( 6.7 m s ) × sin ( 40 ° ) = 4.3 m s Kinematic equation formula for the horizontal position as follows, x f = x i + ( v x ) i Δ t . (3) Here, x i is the initial horizontal distance, Δ t is the time interval. Substitute 0 m for x i in equation (3), we get x f = ( v x ) i Δ t (4) Formula for kinematic equation for the vertical position as follows. y f = y i + ( v y ) i Δ t + 1 2 g ( Δ t ) 2 (5) Here, g is the acceleration due to gravity, y i is the initial vertical distance, Δ t is the time interval, and ( v y ) i is the initial vertical velocity component

4th Edition

ISBN: 9780137574728

Author: Knight

Publisher: PEARSON

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Question

Chapter 3, Problem 73GP

To determine

To explain: The landing distance by the rider from a ramp.

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Chapter 3, Problem 72GP

Chapter 3, Problem 74GP

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