21ST CENT.AST.W/WKBK+SMARTWORK >BI<
6th Edition
ISBN: 9780393415216
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 6QP
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What happens while the elliptical moving planet is closer to the star and far away.
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Saturn is approximately 10 times as far away from the sun as the earth. This means that its orbital acceleration is ________ that of the earth.A. 1/10B. 1/100C. 1/1000D. 1/10,000
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Chapter 3 Solutions
21ST CENT.AST.W/WKBK+SMARTWORK >BI<
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- If a planet had an average distance from the Sun of 10 AU, what would its orbital period be?arrow_forward(a) One of the moons of Jupiter, named Io, has an orbital radius of 4.22 108 m and a period of 1.77 days. Assuming the orbit is circular, calculate the mass of Jupiter, (b) The largest moon of Jupiter, named Ganymede, has an orbital radius of 1.07 109 m and a period of 7.16 days. Calculate the mass of Jupiter from this data, (c) Are your results to parts (a) and (b) consistent? Explain.arrow_forwardNeptune circles the Sun at a distance of 4.50 x 1012 m once every 164 years. Saturn circles the Sun at a distance of 1.43 x 1012 m. What is the orbital period of Saturn? a) 88.6 y 702 b) 109 h C) 29.4 y d) 304 y Boş bırakarrow_forward
- An object is found orbiting the sun at a distance of 70 AU what is the objects orbital period? A. 225 years B. 585 years C. 13.7 years D. 44.8 years E. 127 yearsarrow_forwardA planet’s orbital time period is 29.5 times higher than that of the earth’s orbital period. How far is that planet from the Sun, if the earth is 1.50×108 km away from the sun?arrow_forward3arrow_forward
- Determine what the period of revolution of the Earth would be if its distance from the Sun were 3.5 AU rather than 1 AU. Assume that the mass of the Sun remains the same. The final unit should be y in the answer.arrow_forwardFor the calculation of eccentricity of an elliptical orbit, e = c/a, c is the distance from center to focus. The distance a is accurately described as A. 1/2( focus to focus) B. focus to one end of minor axis C. center to one end of minor axis D. center to perigeearrow_forwardI. Directions: Complete the given table by finding the ratio of the planet's time of revolution to its radius. Average Radius of Orbit Times of Planet R3 T2 T?/R3 Revolution Mercury 5.7869 x 1010 7.605 x 106 Venus 1.081 x 1011 1.941 x 107 Earth 1.496 x 1011 3.156 x 107 1. What pattern do you observe in the last column of data? Which law of Kepler's does this seem to support? II. Solve the given problems. Write your solution on the space provided before each number. 1. You wish to put a 1000-kg satellite into a circular orbit 300 km above the earth's surface. Find the following: a) Speed b) Period c) Radial Acceleration Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer: Given: Unknown: Formula: Solution: Answer:arrow_forward
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