(a) Answer x = 8 Explanation Given: The given equation is: 2 x − 9 = 5 x − 33 Calculation: The solution can be obtained as: 2 x − 9 = 5 x − 33 2 x − 5 x = 9 − 33 − 3 x = − 24 x = 8 (b) To determine Whether the function is linear or non-linear. Answer x = − 16 5 Explanation Given: The given equation is: 5 x − 6 = 10 x + 10 Calculation: The solution can be obtained as: 5 x − 6 = 10 x + 10 5 x − 10 x = 6 + 10 − 5 x = 16 x = − 16 5 (c) To determine Whether the function is linear or non-linear. Answer No solution. Explanation Given: The given equation is: 2 ( 8 x − 3 ) = 4 ( 4 x + 7 ) Calculation: The solution can be obtained as: 2 ( 8 x − 3 ) = 4 ( 4 x + 7 ) 16 x − 6 = 16 x + 7 16 x − 16 x = 6 + 7 0 = 13 This is not possible, hence, no solution. (d) To determine Whether the function is linear or non-linear. Answer x = 2.8 Explanation Given: The given equation is: − 7 x + 5 = 2 ( x − 10.1 ) Calculation: The solution can be obtained as: − 7 x + 5 = 2 ( x − 10.1 ) − 7 x + 5 = 2 x − 20.2 − 7 x − 2 x = − 5 − 20.2 − 9 x = − 25.2 x = 2.8 (e) To determine Whether the function is linear or non-linear. Answer x = − 4 Explanation Given: The given equation is: 6 ( 2 x + 4 ) = 4 ( 4 x + 10 ) Calculation: The solution can be obtained as: 6 ( 2 x + 4 ) = 4 ( 4 x + 10 ) 12 x + 24 = 16 x + 40 12 x − 16 x = 40 − 24 − 4 x = 16 x = − 4 (f) To determine Whether the function is linear or non-linear. Answer No solution. Explanation Given: The given equation is: 8 ( 3 x + 4 ) = 2 ( 12 x + 6 ) Calculation: The solution can be obtained as: 8 ( 3 x + 4 ) = 2 ( 12 x + 6 ) 24 x + 32 = 24 x + 12 24 x − 24 x = 12 − 32 0 = − 20 This is not possible, hence, no solution.

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

16th Edition

ISBN: 9781680331127

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Question

Chapter 3, Problem 6CA

(a)

To determine

Whether the function is linear or non-linear.

(a)

Expert Solution

Answer to Problem 6CA

x=8

Explanation of Solution

Given:

The given equation is:

2x−9=5x−33

Calculation:

The solution can be obtained as:

2x−9=5x−332x−5x=9−33−3x=−24x=8

(b)

To determine

Whether the function is linear or non-linear.

(b)

Expert Solution

Answer to Problem 6CA

x=−165

Explanation of Solution

Given:

The given equation is:

5x−6=10x+10

Calculation:

The solution can be obtained as:

5x−6=10x+105x−10x=6+10−5x=16x=−165

(c)

To determine

Whether the function is linear or non-linear.

(c)

Expert Solution

Answer to Problem 6CA

No solution.

Explanation of Solution

Given:

The given equation is:

2(8x−3)=4(4x+7)

Calculation:

The solution can be obtained as:

2(8x−3)=4(4x+7)16x−6=16x+716x−16x=6+70=13

This is not possible, hence, no solution.

(d)

To determine

Whether the function is linear or non-linear.

(d)

Expert Solution

Answer to Problem 6CA

x=2.8

Explanation of Solution

Given:

The given equation is:

−7x+5=2(x−10.1)

Calculation:

The solution can be obtained as:

−7x+5=2(x−10.1)−7x+5=2x−20.2−7x−2x=−5−20.2−9x=−25.2x=2.8

(e)

To determine

Whether the function is linear or non-linear.

(e)

Expert Solution

Answer to Problem 6CA

x=−4

Explanation of Solution

Given:

The given equation is:

6(2x+4)=4(4x+10)

Calculation:

The solution can be obtained as:

6(2x+4)=4(4x+10)12x+24=16x+4012x−16x=40−24−4x=16x=−4

(f)

To determine

Whether the function is linear or non-linear.

(f)

Expert Solution

Answer to Problem 6CA

No solution.

Explanation of Solution

Given:

The given equation is:

8(3x+4)=2(12x+6)

Calculation:

The solution can be obtained as:

8(3x+4)=2(12x+6)24x+32=24x+1224x−24x=12−320=−20

This is not possible, hence, no solution.

Chapter 3, Problem 5CA

Chapter 3, Problem 7CA

Chapter 3 Solutions

BIG IDEAS MATH Integrated Math 1: Student Edition 2016

Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E

Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - Prob. 42E Ch. 3.1 - Prob. 43E Ch. 3.1 - Prob. 44E Ch. 3.1 - Prob. 45E Ch. 3.1 - Prob. 46E Ch. 3.1 - Prob. 47E Ch. 3.1 - Prob. 48E Ch. 3.1 - Prob. 49E Ch. 3.1 - Prob. 50E Ch. 3.1 - Prob. 51E Ch. 3.2 - Prob. 1E Ch. 3.2 - Prob. 2E Ch. 3.2 - Prob. 3E Ch. 3.2 - Prob. 4E Ch. 3.2 - Prob. 5E Ch. 3.2 - Prob. 6E Ch. 3.2 - Prob. 7E Ch. 3.2 - Prob. 8E Ch. 3.2 - Prob. 9E Ch. 3.2 - 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