Chemistry (OER)
19th Edition
ISBN: 9781947172623
Author: OpenStax
Publisher: OpenStax College
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Textbook Question
Chapter 3, Problem 61E
What volume of a
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Hi!!
Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required.
Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!
. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
2°C. +2°C. < cleavage
Bond A
• CH3 + 26. t cleavage
2°C• +3°C•
Bond C
Cleavage
CH3 ZC
'2°C. 26.
E
Strongest
3°C. 2C.
Gund
Largest
BDE
weakest bond
In that molecule
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
C bond
Produces
A
Weakest
Bond
Most
Strongest
Bond
Stable radical
Strongest Gund
produces least stable
radicals
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
人
8°C. formed in
bound C
cleavage
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
methyl radical
•CH3
formed in
bund A Cleavage
Which carbocation is more stable?
Chapter 3 Solutions
Chemistry (OER)
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY