Fluid Mechanics (2nd Edition)
2nd Edition
ISBN: 9780134649290
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 3, Problem 5FP
To determine
The magnitude of the local and convective acceleration.
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I need help with a MATLAB code. This code just keeps running and does not give me any plots. I even reduced the tolerance from 1e-9 to 1e-6. Can you help me fix this? Please make sure your solution runs.
% Initial Conditions
rev = 0:0.001:2;
g1 = deg2rad(1);
g2 = deg2rad(3);
g3 = deg2rad(6);
g4 = deg2rad(30);
g0 = deg2rad(0);
Z0 = 0;
w0 = [0; Z0*cos(g0); -Z0*sin(g0)];
Z1 = 5;
w1 = [0; Z1*cos(g1); -Z1*sin(g1)];
Z2 = 11;
w2 = [0; Z2*cos(g2); -Z2*sin(g2)];
[v3, psi3, eta3] = Nut_angle(Z2, g2, w2);
plot(v3, psi3)
function dwedt = K_DDE(~, w_en)
% Extracting the initial condtions to a variable
% Extracting the initial condtions to a variable
w = w_en(1:3);
e = w_en(4:7);
Z = w_en(8);
I = 0.060214;
J = 0.015707;
x = (J/I) - 1;
y = Z - 1;
s = Z;
% Kinematic Differential Equations
dedt = zeros(4,1);
dedt(1) = pi*(e(3)*(s-w(2)-1) + e(2)*w(3) + e(4)*w(1));
dedt(2) = pi*(e(4)*(w(2)-1-s) + e(3)*w(1) - e(1)*w(3));
dedt(3) = pi*(-e(1)*(s-w(2)-1) - e(2)*w(1) + e(4)*w(3));…
Chapter 3 Solutions
Fluid Mechanics (2nd Edition)
Ch. 3 - Prob. 1FPCh. 3 - A two-dimensional flow field is defined by u =...Ch. 3 - Prob. 3FPCh. 3 - The velocity of particles of dioxitol along the x...Ch. 3 - Prob. 5FPCh. 3 - Fluid flows through the curved pipe at a steady...Ch. 3 - Prob. 7FPCh. 3 - Fluid flows through the curved pipe such that...Ch. 3 - A two-dimensional flow field for a fluid can be...Ch. 3 - A two-dimensional flow field for a liquid can be...
Ch. 3 - A two-dimensional flow field for a fluid is...Ch. 3 - Prob. 4PCh. 3 - A flow field is defined by u = (2x2 + 1) m/s and υ...Ch. 3 - A flow field for a fluid is defined by u = (2 + y)...Ch. 3 - Particles travel within a flow field defined by V...Ch. 3 - Particles travel within a flow field defined by V...Ch. 3 - A flow field is defined by u = 10 m/s and υ = −3...Ch. 3 - A balloon is released into the air from the origin...Ch. 3 - A balloon is released into the air from point (1...Ch. 3 - Prob. 12PCh. 3 - A fluid has velocity components of u = (3x2 + 1)...Ch. 3 - A particle travels along the streamline defined by...Ch. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - A particle travels along a streamline defined by...Ch. 3 - Prob. 20PCh. 3 - The circulation of a fluid is defined by the...Ch. 3 - Prob. 22PCh. 3 - A two-dimensional flow field for benzene is...Ch. 3 - Air flows uniformly through the center of a...Ch. 3 - Oil flows through the reducer such that particles...Ch. 3 - A fluid has velocity components of u=(116x2yt)...Ch. 3 - A fluid flow is defined by u = (6x2 − 3y2) m/s and...Ch. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - A fluid flow is defined by u = (4xy) ft/s and υ =...Ch. 3 - Oil flows through the reducer such that particles...Ch. 3 - A fluid flow is defined by u=(14y2)m/s and...Ch. 3 - Prob. 33PCh. 3 - A fluid flow is defined by u = (0.5y) m/s and υ =...Ch. 3 - A velocity field for oil is defined by u = (3y)...Ch. 3 - The velocity for the flow of a gas along the...Ch. 3 - Prob. 37PCh. 3 - Air flowing through the center of the duct...Ch. 3 - A fluid flow is defined by u = (8t2) m/s and υ =...Ch. 3 - A fluid flow is defined by V = {4xi + 2j} m/s,...Ch. 3 - A fluid flow is defined by u = (2x2 − y2) m/s and...Ch. 3 - A fluid flow is defined by u = (2y2) m/s and υ =...Ch. 3 - The velocity of gasoline, along the centerline of...Ch. 3 - Prob. 44PCh. 3 - A fluid flow is defined by V = {4yi + 2xj} m/s,...Ch. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - As water flows steadily over the spillway, one of...Ch. 3 - Water flows into the drainpipe such that it only...Ch. 3 - The motion of a tornado can, in part, be described...Ch. 3 - A particle located at a point within a fluid flow...Ch. 3 - A particle moves along the circular streamline,...Ch. 3 - Air flows around the front circular surface. If...Ch. 3 - Fluid particles have velocity components of u =...Ch. 3 - A fluid has velocity components of u = (4xy) m/s...
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- alpha 1 is not zero alpha 1 can equal alpha 2 use velocity triangle to solve for alpha 1 USE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',...…arrow_forward3. Find a basis of eigenvectors and diagonalize. 4 0 -19 7 a. b. 1-42 16 12-20 [21-61arrow_forward2. Find the eigenvalues. Find the corresponding eigenvectors. 6 2 -21 [0 -3 1 3 31 a. 2 5 0 b. 3 0 -6 C. 1 1 0 -2 0 7 L6 6 0 1 1 2. (Hint: λ = = 3)arrow_forward
- USE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow) R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),...…arrow_forwardUSE MATLAB ONLY provide typed code solve for velocity triangle and dont provide copied answer Turbomachienery . GIven: vx = 185 m/s, flow angle = 60 degrees, R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3 Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram Use this code for plot % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3) S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)]; S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)]; U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)]; S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)]; U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)]; plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',... S3L,V3x,'k',S3L,V3r,'r',S3L,W3r,'b',U3x,U3y,'g',...... 'LineWidth',2,'MarkerSize',10),... axis([-1 6 -4 4]), ...…arrow_forwardThe answer should equal to 1157. Please sent me the solution. Thank you!arrow_forward
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