Fluid Mechanics (2nd Edition)
2nd Edition
ISBN: 9780134649290
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 3, Problem 25P
To determine
The acceleration of the oil particles at a distance of
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Chapter 3 Solutions
Fluid Mechanics (2nd Edition)
Ch. 3 - Prob. 1FPCh. 3 - A two-dimensional flow field is defined by u =...Ch. 3 - Prob. 3FPCh. 3 - The velocity of particles of dioxitol along the x...Ch. 3 - Prob. 5FPCh. 3 - Fluid flows through the curved pipe at a steady...Ch. 3 - Prob. 7FPCh. 3 - Fluid flows through the curved pipe such that...Ch. 3 - A two-dimensional flow field for a fluid can be...Ch. 3 - A two-dimensional flow field for a liquid can be...
Ch. 3 - A two-dimensional flow field for a fluid is...Ch. 3 - Prob. 4PCh. 3 - A flow field is defined by u = (2x2 + 1) m/s and υ...Ch. 3 - A flow field for a fluid is defined by u = (2 + y)...Ch. 3 - Particles travel within a flow field defined by V...Ch. 3 - Particles travel within a flow field defined by V...Ch. 3 - A flow field is defined by u = 10 m/s and υ = −3...Ch. 3 - A balloon is released into the air from the origin...Ch. 3 - A balloon is released into the air from point (1...Ch. 3 - Prob. 12PCh. 3 - A fluid has velocity components of u = (3x2 + 1)...Ch. 3 - A particle travels along the streamline defined by...Ch. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - A particle travels along a streamline defined by...Ch. 3 - Prob. 20PCh. 3 - The circulation of a fluid is defined by the...Ch. 3 - Prob. 22PCh. 3 - A two-dimensional flow field for benzene is...Ch. 3 - Air flows uniformly through the center of a...Ch. 3 - Oil flows through the reducer such that particles...Ch. 3 - A fluid has velocity components of u=(116x2yt)...Ch. 3 - A fluid flow is defined by u = (6x2 − 3y2) m/s and...Ch. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - A fluid flow is defined by u = (4xy) ft/s and υ =...Ch. 3 - Oil flows through the reducer such that particles...Ch. 3 - A fluid flow is defined by u=(14y2)m/s and...Ch. 3 - Prob. 33PCh. 3 - A fluid flow is defined by u = (0.5y) m/s and υ =...Ch. 3 - A velocity field for oil is defined by u = (3y)...Ch. 3 - The velocity for the flow of a gas along the...Ch. 3 - Prob. 37PCh. 3 - Air flowing through the center of the duct...Ch. 3 - A fluid flow is defined by u = (8t2) m/s and υ =...Ch. 3 - A fluid flow is defined by V = {4xi + 2j} m/s,...Ch. 3 - A fluid flow is defined by u = (2x2 − y2) m/s and...Ch. 3 - A fluid flow is defined by u = (2y2) m/s and υ =...Ch. 3 - The velocity of gasoline, along the centerline of...Ch. 3 - Prob. 44PCh. 3 - A fluid flow is defined by V = {4yi + 2xj} m/s,...Ch. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - As water flows steadily over the spillway, one of...Ch. 3 - Water flows into the drainpipe such that it only...Ch. 3 - The motion of a tornado can, in part, be described...Ch. 3 - A particle located at a point within a fluid flow...Ch. 3 - A particle moves along the circular streamline,...Ch. 3 - Air flows around the front circular surface. If...Ch. 3 - Fluid particles have velocity components of u =...Ch. 3 - A fluid has velocity components of u = (4xy) m/s...
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- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
- An experimental setup is being built to study the flow in a large water main (i.e., a large pipe). The water main is expected to convey a discharge (Qp). The experimental tube will be built at a length scale of 1/20 of the actual water main. After building the experimental setup, the pressure drop per unit length in the model tube (APm/Lm) is measured. Problem (20): Given the value of APm/Lm [kPa/m], and assuming pressure coefficient similitude, calculate the drop in the pressure per unit length of the water main (APP/Lp) in [Pa/m]. Givens: AP M/L m = 590.637 kPa/m meen Answers: ( 1 ) 59.369 Pa/m ( 2 ) 73.83 Pa/m (3) 95.443 Pa/m ( 4 ) 44.444 Pa/m *******arrow_forwardFind the reaction force in y if Ain = 0.169 m^2, Aout = 0.143 m^2, p_in = 0.552 atm, Q = 0.367 m^3/s, α = 31.72 degrees. The pipe is flat on the ground so do not factor in weight of the pipe and fluid.arrow_forwardFind the reaction force in x if Ain = 0.301 m^2, Aout = 0.177 m^2, p_in = 1.338 atm, Q = 0.669 m^3/s, and α = 37.183 degreesarrow_forward
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