For any positive integer n and any angle θ , show that in the group S L ( 2 , R ) , [ cos θ − sin θ sin θ cos θ ] = [ cos n θ − sin n θ sin n θ cos n θ ] .Use this formula to find the order of [ cos 60 ° − sin 60 ° sin 60 ° cos 60 ° ] = [ cos 2 ° − sin 2 ° sin 2 ° cos 2 ° ] .(Geometrically, [ cos θ − sin θ sin θ cos θ ] represents a rotation of the plane θ degrees.)
For any positive integer n and any angle θ , show that in the group S L ( 2 , R ) , [ cos θ − sin θ sin θ cos θ ] = [ cos n θ − sin n θ sin n θ cos n θ ] .Use this formula to find the order of [ cos 60 ° − sin 60 ° sin 60 ° cos 60 ° ] = [ cos 2 ° − sin 2 ° sin 2 ° cos 2 ° ] .(Geometrically, [ cos θ − sin θ sin θ cos θ ] represents a rotation of the plane θ degrees.)
Solution Summary: The author explains that G is the symmetry group of a circle. As n increases to infinity, the polygon becomes symmetric.
For any positive integer n and any angle
θ
, show that in the group
S
L
(
2
,
R
)
,
[
cos
θ
−
sin
θ
sin
θ
cos
θ
]
=
[
cos
n
θ
−
sin
n
θ
sin
n
θ
cos
n
θ
]
.Use this formula to find the order of
[
cos
60
°
−
sin
60
°
sin
60
°
cos
60
°
]
=
[
cos
2
°
−
sin
2
°
sin
2
°
cos
2
°
]
.(Geometrically,
[
cos
θ
−
sin
θ
sin
θ
cos
θ
]
represents a rotation of the plane
θ
degrees.)
Solve questions by Course Name (Ordinary Differential Equations II 2)
please Solve questions by Course Name( Ordinary Differential Equations II 2)
InThe Northern Lights are bright flashes of colored light between 50 and 200 miles above Earth.
Suppose a flash occurs 150 miles above Earth. What is the measure of arc BD, the portion of Earth
from which the flash is visible? (Earth’s radius is approximately 4000 miles.)
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