For each divisor k > 1 of n , let U k ( n ) = { x ∈ U ( n ) | x mod k = 1 } .[For example, U 3 ( 21 ) = { 1 , 4 , 10 , 13 , 16 , 19 } and U 7 ( 21 ) = { 1 , 8 } .]List the elements of U 4 ( 20 ) , U 5 ( 20 ) , U 5 ( 30 ) , and U 10 ( 30 ) . Prove that U k ( n ) is a subgroup of U ( n ). Let H = { x ∈ U ( 10 ) | x mod 3 = 1 } . Is H a subgroup of U (10)? (This exercise is referred to in Chapter 8.)
For each divisor k > 1 of n , let U k ( n ) = { x ∈ U ( n ) | x mod k = 1 } .[For example, U 3 ( 21 ) = { 1 , 4 , 10 , 13 , 16 , 19 } and U 7 ( 21 ) = { 1 , 8 } .]List the elements of U 4 ( 20 ) , U 5 ( 20 ) , U 5 ( 30 ) , and U 10 ( 30 ) . Prove that U k ( n ) is a subgroup of U ( n ). Let H = { x ∈ U ( 10 ) | x mod 3 = 1 } . Is H a subgroup of U (10)? (This exercise is referred to in Chapter 8.)
Solution Summary: The author explains that U_k(n) is a subgroup of
For each divisor
k
>
1
of n, let
U
k
(
n
)
=
{
x
∈
U
(
n
)
|
x
mod
k
=
1
}
.[For example,
U
3
(
21
)
=
{
1
,
4
,
10
,
13
,
16
,
19
}
and
U
7
(
21
)
=
{
1
,
8
}
.]List the elements of
U
4
(
20
)
,
U
5
(
20
)
,
U
5
(
30
)
,
and
U
10
(
30
)
. Prove that
U
k
(
n
)
is a subgroup of U(n). Let
H
=
{
x
∈
U
(
10
)
|
x
mod
3
=
1
}
. Is H a subgroup of U(10)? (This exercise is referred to in Chapter 8.)
Solutions of inequalitie
Google Classroom
Mic
Is (-3, 2) a solution of 7x+9y > -3?
Choose 1 answer:
A
Yes
B
No
Related content
▶6:06
Testing solutions to inequalities
2 of 4
Are natural logarithms used in real life ? How ? Can u give me two or three ways we can use them. Thanks
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.