Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
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Chapter 3, Problem 50P
Summary Introduction
To determine: The method of production of yellow many loculed tall pure line.
Introduction. The dominant allele masks the expression of the recessive allele. Therefore the dominant allele is expressed in homozygous and heterozygous genotype while the recessive
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At least two pairs of genes control eye color. Both pairs influence the production of the pigment, melanin, but act independently. One pair of alleles is B (Brown color; dominant) and b (blue color); the other pair is A (pigment production; dominant) and a (no pigment production; albino). The gene pair aais epistatic to (masks) B and b and produces the nonpigmented eyes of the albino. What is the typeof gene interaction that exists between the two gene pairs?
Give the genotypes and phenotypes of the possible offspring of the mating bbAa x Bbaa andi ndicate the parental phenotypes. (any method)
A common kind of red-green blindness in humans is caused by the presence of a sex-linked recessive gene c, whose normal allele is c+. Using these genes, what are the possible genotypes and their corresponding phenotypes in males and females? Can two colorblind parents produce a normal son? (b) A normal daughter? (c) Can two normal parents produce a colorblind son? (d) a colorblind daughter?
Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
Chapter 3 Solutions
Introduction to Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13P
Ch. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 31.1PCh. 3 - Prob. 31.2PCh. 3 - Prob. 31.3PCh. 3 - Prob. 31.4PCh. 3 - Prob. 31.5PCh. 3 - Prob. 31.6PCh. 3 - Prob. 31.7PCh. 3 - Prob. 31.8PCh. 3 - Prob. 31.9PCh. 3 - Prob. 31.10PCh. 3 - Prob. 31.11PCh. 3 - Prob. 31.12PCh. 3 - Prob. 31.13PCh. 3 - Prob. 31.14PCh. 3 - Prob. 31.15PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 57P
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- In human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the genotype of the woman's father? What is the probability that the couple's first child will be a non-freckled, normal visioned girl? What is the probability that the first two children born to the couple will be freckled and colorblind girls?arrow_forwardIn human beings, the gene for red‑green colorblindness (r) is sex‑linked and recessive to its allele for normal vision (R), while the gene for freckles (F) is autosomal and dominant over its allele for nonfreckled (f). A nonfreckled, normal‑visioned woman whose father was freckled and colorblind, marries a freckled, colorblind man whose mother was nonfreckled. What is the probability that the first child born to the couple will either be a freckled, colorblind boy or a non‑freckled, normal visioned girl or a non-freckled, normal visioned boy? What is the probability that the first four children born to the couple will be freckled and normal visioned girls?arrow_forwardRegarding Mendelian inheritance in diploid individuals, (Read each statement carefully. Select all of the statements below that are true (that you agree with). Leave any statements that are false (that you do not agree with) un- selected.) a diploid individual receives two copies of every autosome from the previous generation. for every autosomal gene inherited by an individual, both copies can come from one parent. a diploid individual gives two copies of every autosome to a child in the next generation. to be diploid means that two independent genes are specified in the individual's genotype.arrow_forward
- Red-green color blindness, in humans, is a sex-linked trait controlled by alleles on the X chromosome. Normal color vision (X+) is dominant to colorblindness (Xc). (NOTE: You could write this as XC for the normal allele and Xc for the recessive colorblind allele. Unfortunately, capital C and lowercase c are hard to tell apart as superscripts, especially in type. I will use C -- "X-plus" -- for the normal allele.) If a colorblind man marries a woman with normal vision and they have a colorblind son, what are the genotypes of the father and the mother?arrow_forwardIn humans, hemophilia is an X-linked recessive disorder that affects the gene for factor VIII protein, which is essential for blood clotting. The dominant and recessive alleles for the factor VIII gene are represented by H and h. Albinism is an autosomal recessive condition involving the tyrosinase enzyme which synthesizes pigment. Alleles of tyrosinase are represented by A and a. The provided pedigree shows a new marriage between Clara and Charles. A) Review the pedigree, filling in any genotypes that can be determined from the displayed traits. B) What is the probability that their first child will display hemophilia, albinism, or BOTH hemophilia AND albinism.C) If Clara and Charles first child has albinism, what is the probability that the second child will also display albinism?arrow_forwardIn humans, one of the genes determining color vision islocated on the X chromosome. The dominant form (C )produces normal color vision; red-green color deficiency(c) is recessive. If a man with normal color visionmarries a color-deficient woman, what is the probabilityof them having a color-deficient son? A color-deficientdaughter?arrow_forward
- In humans, color vision depends on genes encodingthree pigments. The R (red pigment) and G (green pigment) genes are close together on the X chromosome,whereas the B (blue pigment) gene is autosomal. A recessive mutation in any one of these genes can cause colorblindness. Suppose that a color-blind man married awoman with normal color vision. The four sons from thismarriage were color-blind, and the five daughters werenormal. Specify the most likely genotypes of both parents and their children, explaining your reasoning. (Apedigree drawing will probably be helpful.) (Problem 50is by Rosemary Redfield.)arrow_forwardIn humans, the genetic disease cystic fibrosis is caused by a recessive allele (a). The normal (healthy) allele is dominant (A). What is the genotype of someone who has cystic fibrosis? What are the two different genotypes that a healthy person could have? If two people were both heterozygous for the cystic fibrosis gene, what fraction of their children would be likely to have this disease? Hint: Draw a Punnett square to figure it out.arrow_forwardIn man, muscular dystrophy is a condition in which the muscles waste away during early life and may result in a shorter life expectancy. It is due to a sex-linked, recessive gene. A certain couple has five children – three boys (ages 1yr, 3yrs, and 10yrs old) and two girls (ages 5yrs and 7yrs old). The oldest boy shows the symptoms of this disease. You are their family physician and they come to you for advice. What would you tell them about the chances of their other children developing the disease?arrow_forward
- Alleles of a single gene control whether individuals have a "hitchhiker's thumb" or "straight thumb." You are studying the inheritance of hitchhiker's thumb (straight thumb is dominant) in your family. Assuming that this trait is inherited on an autosome (ie, not a sex-chromosome), please answer which of the following outcomes ARE POSSIBLE under normal circumstances. (Choose all that apply.) 1) Two parents have straight thumb, but they have a child with hitchhiker's thumb. 2) Two parents have hitchhiker's thumb, but they have a child with straight thumb. 3) Mother has straight thumb, father has hitchhiker's thumb, child is homozygous dominant for the allele. 4) Mother has straight thumb, father has hitchhiker's thumb. They have one child with straight thumb, another child with hitchhiker's thumb.arrow_forwardAnhidrotic ectodermal dysplasia is an X-linked recessive disorder in humans characterized by small teeth, no sweat glands, and sparse body hair. This trait is usually seen in men, but women who are heterozygous carriers of the trait often have irregular patches of skin with few or no sweat glands (see the illustration below). a. Explain why women who are heterozygous carriers of a recessive gene for anhidrotic ectodermal dysplasia have irregular patches of skin lacking sweat glands. b. Why does the distribution of the patches of skin lacking sweat glands differ among the females depicted in the illustration, even between the identical twins?arrow_forwardConsider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?arrow_forward
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