OPERATIONS MANAGEMENT LL W/CONNECT CODE
OPERATIONS MANAGEMENT LL W/CONNECT CODE
2nd Edition
ISBN: 9781266520037
Author: CACHON
Publisher: MCG CUSTOM
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Chapter 3, Problem 4PA

a)

Summary Introduction

To draw: A process flow diagram for this process.

a)

Expert Solution
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Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  1

Process flow diagram:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  2

b)

Summary Introduction

To determine: The capacity at the resource “Apply a lid”.

b)

Expert Solution
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Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  3

Calculation of capacity:

Capacity=Number of machines×Seconds per hourSeconds per bottle=1×3,6003=1,200 bottles

The capacity is 1,200 bottles.

c)

Summary Introduction

To determine: The bottleneck in the process.

c)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  4

Determination of bottleneck:

The process step with the longest processing time “seconds per bottle” is the bottleneck in the process. Packaging has the highest time of 3 seconds per bottle.

Hence, the bottleneck is Packaging.

d)

Summary Introduction

To determine: The flow rate.

d)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  5

Determination of flow rate:

Flow rate=Seconds per hourBottleneck capacity=3,6004=900 bottles

The flow rate is 900 bottles.

e)

Summary Introduction

To determine: The utilization of resource “Apply a lid”

e)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  6

Calculation of utilization:

Utilization=Flow rateCapacity×100=900Number of machines×Seconds per hourSeconds per bottle×100=9001×3,6003×100=9001,200×100=75%

The utilization is 75%.

f)

Summary Introduction

To determine: The utilization of bottling.

f)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  7

Calculation of utilization:

Utilization=Flow rateCapacity×100=Number of machinesSeconds per minuteDemand per minuteSeconds per bottle×100=160121×100=151×100=20%

The utilization is 20%.

g)

Summary Introduction

To determine: The cycle time of the process.

g)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  8

Calculation of cycle time:

The demand is constrained and has a flow rate of

Flow rate=Number of machinesSeconds per minuteDemand per minute=16012=0.20 bottle per second

Cycle time=1Flow rate=10.2=5 seconds

The cycle time is 5 seconds.

h)

Summary Introduction

To determine: The time taken to produce 500 bottles.

h)

Expert Solution
Check Mark

Explanation of Solution

Given information:

OPERATIONS MANAGEMENT LL W/CONNECT CODE, Chapter 3, Problem 4PA , additional homework tip  9

Calculation of time taken to produce 500 bottles:

Time taken=(4×5)+[(500-1)×5]=20+(499×5)=20+2,495=2,515 seconds

The time taken to produce 500 bottles is 2,515 seconds.

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