Chapter 3, Problem 49E

Interpretation Introduction

Interpretation:

$\text{Copper}\left(\text{II}\right)\text{fluoride}$ is given to contain $37.4\%\text{F}$ by mass. The mass of fluorine contained in $72.4\text{g}$ of $\text{Copper}\left(\text{II}\right)\text{fluoride}$ is to be calculated.

Concept introduction: Formula mass is defined as average mass of atoms present in the chemical formula. It is the sum of the atomic masses of all the atoms present in the chemical formula of any compound.

The formula to calculate number of moles is,
   $n=\frac{m}{M_w}$

To determine: The mass of fluorine in $72.4\text{g}$ of $\text{Copper}\left(\text{II}\right)\text{fluoride}$ .