Explanation Let the puck’s moves from the origin. Write the expression for displacement in the x direction. x = v 0 t + 1 2 a x t 2 (I) Here, v 0 is the initial velocity, t is the time, and a x is the acceleration in the x direction. Write the expression for displacement in the y direction. y = 1 2 a y t 2 (II) Here, a y is he acceleration in the y direction. Write the expression for final position. r = x 2 + y 2 (II) Use equation (I) and (II) in (III). r = ( v 0 t + 1 2 a x t 2 ) 2 + ( 1 2 a y t 2 ) 2 (IV) Substitute, a cos θ for a x , and a sin θ for a y in the equation (IV), and square the equation. r 2 = ( v 0 t + 1 2 a cos θ t 2 ) 2 + ( 1 2 a sin θ t 2 ) 2 (V) Conclusion: Substitute, 27.7 m / s for v 0 , 0

4th Edition

ISBN: 9780134988559

Author: Wolfson, Richard

Publisher: Pearson Education,

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Chapter 3, Problem 47E

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The magnitude of pucks acceleration.

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Chapter 3, Problem 46E

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