Chapter 3, Problem 40PP

Interpretation Introduction

Interpretation:

The reaction between ${\text{H}}_{\text{2}}\text{O}$ and ${\text{NaNH}}_{\text{2}}{\text{/NH}}_{\text{3}}$ should be predicted.

Concept introduction:

Reaction of ${\text{NaNH}}_{\text{2}}{\text{/NH}}_{\text{3}}$ with ${\text{H}}_{\text{2}}\text{O}$ is an acid-base reaction.

According to Bronsted-Lowery acid–base theory, proton acceptor is base and proton donor is treated as acid.

Example:

$\begin{array}{l}{\text{HA+B}}^{\text{-}}\stackrel{}{\to }{\text{HB+A}}^{\text{-}}\\ \text{HA}\text{=}\text{acid}\\ {\text{B}}^{\text{-}}\text{=}\text{base}\end{array}$

To identify: The acid and base between ${\text{NaNH}}_{\text{2}}{\text{/NH}}_{\text{3}}$ and ${\text{H}}_{\text{2}}\text{O}$.