OPENINTRO:STATISTICS
4th Edition
ISBN: 9781943450077
Author: OPENINTRO
Publisher: amazon.com
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Chapter 3, Problem 39CE
To determine
Check whether each row of given distribution is valid or invalid.
Expert Solution & Answer
Answer to Problem 39CE
The
Explanation of Solution
From the given grade distribution, row (a) values are 0.3, 0.3, 0.3, 0.2, and 0.1.
The valid
Here, the sum of probability is calculated as follows:
Thus, row (a) is an invalid probability distribution since the total probability is greater than 1.
From the given grade distribution, row (b) values are 0, 0, 1, 0, and 0.
The valid probability distribution should have total probability equal to 1 and probability values should be greater than or equal to zero.
Here, the sum of probability is calculated as follows:
Thus, row (b) is a valid probability distribution since the total probability is equal than 1.
From the given grade distribution, row (c) values are 0.3, 0.3, 0.3, 0, and 0.
The valid probability distribution should have a total probability equal to 1.
Here, the sum of probability is calculated as follows:
Thus, row (c) is an invalid probability distribution since the total probability is less than 1.
From the given grade distribution, row (d) values are 0.3, 0.5, 0.2, 0.1, and –0.1.
The valid probability distribution should have a total probability equal to 1 and probability values should be greater than or equal to zero.
Here, the negative probability value is given.
Thus, row (d) is an invalid probability distribution since the negative probability value is found.
From the given grade distribution, row (e) values are 0.2, 0.4, 0.2, 0.1, and 0.1.
The valid probability distribution should have a total probability equal to 1 and probability values should be greater than or equal to zero.
Here, the sum of probability is calculated as follows:
Thus, row (e) is a valid probability distribution since the total probability is equal than 1.
From the given grade distribution, row (f) values are 0, –0.1, 1.1, 0, and 0.
The valid probability distribution should have a total probability equal to 1 and probability values should be greater than or equal to zero.
Here, the negative probability value is given.
Thus, row (f) is an invalid probability distribution since negative probability value is found.
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Students have asked these similar questions
Section 2.2 Subsets
71
Exercise Set 2.2
Practice Exercises
In Exercises 1-18, write or in each blank so that the resulting
statement is true.
1. {1, 2, 5}
{1, 2, 3, 4, 5, 6, 7}
2. {2, 3, 7}
{1, 2, 3, 4, 5, 6, 7}
3. {-3, 0, 3}
{-4,-3,-1, 1, 3, 4}
4. {-4, 0, 4}
5. {Monday, Friday}
{-3, -1, 1, 3}
{Saturday, Sunday, Monday, Tuesday, Wednesday}
6. {Mercury, Venus, Earth}
{Venus, Earth, Mars, Jupiter}
7. {x/x is a cat}
{xx is a black cat}
{x|x is a pure-bred dog}
ibrary
mbers,
ause the
entire
sual
8. {xx is a dog}
9. (c, o, n, v, e, r, s, a, t, i, o, n}
{v, o, i, c, e, s, r, a, n, t, o, n}
10. [r, e, v, o, l, u, t, i, o, n}
{t, o, l, o, v, e, r, u, i, n}
33. A = {x|x E N
and
5 < x < 12}
B
=
{x|x E N
and
2 ≤ x ≤ 11}
A_ B
34. A =
{x|x = N
and
3 < x < 10}
B =
A.
{x|x = N
and
2 ≤ x ≤ 8}
B
35. Ø
{7, 8, 9,..., 100}
36. Ø
_{101, 102, 103, . . ., 200}
37. [7, 8, 9,...}
38. [101, 102, 103, ...}
39. Ø
40. { }
{ }
e
In Exercises 41-54, determine whether each statement is true or
false. If…
A = 5.8271 ± 0.1497
=
B 1.77872 ± 0.01133
C=0.57729 ± 0.00908
1. Find the relative uncertainty of A, B, and C
2. Find A-3
3. Find 7B
4. Find A + B
5. Find A B-B
-
6. Find A * B
7. Find C/B
8. Find 3/A
9. Find A 0.3B
-
10. Find C/T
11. Find 1/√A
12. Find AB²
Why charts,graphs,table??? difference between regression and correlation analysis.
Chapter 3 Solutions
OPENINTRO:STATISTICS
Ch. 3.1 - Prob. 6GPCh. 3.1 - Prob. 7GPCh. 3.1 - Prob. 8GPCh. 3.1 - Prob. 9GPCh. 3.1 - Prob. 10GPCh. 3.1 - Prob. 11GPCh. 3.1 - Prob. 12GPCh. 3.1 - Prob. 13GPCh. 3.1 - Prob. 14GPCh. 3.1 - Prob. 15GP
Ch. 3.1 - Prob. 16GPCh. 3.1 - Prob. 17GPCh. 3.1 - Prob. 18GPCh. 3.1 - Prob. 19GPCh. 3.1 - Prob. 20GPCh. 3.1 - Prob. 22GPCh. 3.1 - Prob. 23GPCh. 3.1 - Prob. 24GPCh. 3.1 - Prob. 1ECh. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10ECh. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.2 - Prob. 28GPCh. 3.2 - Prob. 29GPCh. 3.2 - Prob. 30GPCh. 3.2 - Prob. 31GPCh. 3.2 - Prob. 32GPCh. 3.2 - Prob. 33GPCh. 3.2 - Prob. 35GPCh. 3.2 - Prob. 36GPCh. 3.2 - Prob. 37GPCh. 3.2 - Prob. 38GPCh. 3.2 - Prob. 39GPCh. 3.2 - Prob. 41GPCh. 3.2 - Prob. 43GPCh. 3.2 - Prob. 45GPCh. 3.2 - Prob. 46GPCh. 3.2 - Prob. 13ECh. 3.2 - Prob. 14ECh. 3.2 - Prob. 15ECh. 3.2 - Prob. 16ECh. 3.2 - Prob. 17ECh. 3.2 - Prob. 18ECh. 3.2 - Prob. 19ECh. 3.2 - Prob. 20ECh. 3.2 - Prob. 21ECh. 3.2 - Prob. 22ECh. 3.3 - Prob. 49GPCh. 3.3 - Prob. 51GPCh. 3.3 - Prob. 52GPCh. 3.3 - Prob. 53GPCh. 3.3 - Prob. 23ECh. 3.3 - Prob. 24ECh. 3.3 - Prob. 25ECh. 3.3 - Prob. 26ECh. 3.3 - Prob. 27ECh. 3.3 - Prob. 28ECh. 3.4 - Prob. 55GPCh. 3.4 - Prob. 59GPCh. 3.4 - Prob. 62GPCh. 3.4 - Prob. 63GPCh. 3.4 - Prob. 64GPCh. 3.4 - Prob. 66GPCh. 3.4 - Prob. 67GPCh. 3.4 - Prob. 69GPCh. 3.4 - Prob. 70GPCh. 3.4 - Prob. 29ECh. 3.4 - Prob. 30ECh. 3.4 - Prob. 31ECh. 3.4 - Prob. 32ECh. 3.4 - Prob. 33ECh. 3.4 - Prob. 34ECh. 3.4 - Prob. 35ECh. 3.4 - Prob. 36ECh. 3.5 - Prob. 73GPCh. 3.5 - Prob. 75GPCh. 3.5 - Prob. 37ECh. 3.5 - Prob. 38ECh. 3 - Prob. 39CECh. 3 - Prob. 40CECh. 3 - Prob. 41CECh. 3 - Prob. 42CECh. 3 - Prob. 43CECh. 3 - Prob. 44CECh. 3 - Prob. 45CECh. 3 - Prob. 46CECh. 3 - Prob. 47CE
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