Explanation Given information: Inductance of inductor1 is 40 mH Inductance of the inductor2 is 30 mH Mutual inductance is 20 mH The current through the inductor 1 is given by i t = 2 cos ( 500 t ) A The current through the inductor 2 is given by i 2 ( t ) = 2 e − 400 t A . Calculation: The circuit can be drawn as For the inductor L 1 , the expression for the voltage across it is given by expression: v 1 ( t ) = L 1 d i 1 d t + M − d i 2 d t ......................... ( 1 ) Where, L 1 is the inductance of the inductor 1. d i 1 d t is the rate of change of the current through inductor 1. M is the mutual inductance. d i 2 d t is the rate of change of the current through inductor 2. Plugging the given values in equation (1), v 1 ( t ) = 40 × 10 − 3 d d t ( 2 cos ( 500 t ) ) + ( 20 × 10 − 3 ) d d

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ISBN: 8220106714201

Author: HAMBLEY

Publisher: YUZU

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Chapter 3, Problem 3.7PT

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The expression of the voltages v1(t) and v2(t) across the given inductors L1 and L2.

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Chapter 3, Problem 3.6PT

Chapter 3, Problem 3.8PT

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The expression of the voltages v 1 ( t ) and v 2 ( t ) across the given inductors L 1 and L 2 .

Solution Summary: The author explains the expression of the voltages across the given inductors L_1 and the mutual inductance.

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