
Concept explainers
(a)
Interpretation:
The number of protons, neutrons and electrons present in the atom of
Concept Introduction:
Mass number is the sum of the number of protons and neutrons inside the nucleus of an atom. This gives the number of subatomic particle present inside the nucleus. Mass number is represented by the symbol A.
From atomic number and mass number, the number of each sub atomic particle can be found.
Complete chemical symbol notation can be given as.
An element is a pure substance that cannot be broken by ordinary
(a)

Explanation of Solution
Given atom is
Atomic number is given as 50 and mass number is given as 118.
Therefore, the number of protons is 50, number of electrons is 50, and number of neutrons is 68.
The number of protons, electrons and neutrons present in the atom is given.
(b)
Interpretation:
The number of protons, neutrons and electrons present in the atom of
Concept Introduction:
Atomic number for each and every element is a unique one. This is the total number of protons that is present in an atom. As the atom is electrically neutral, it can also be said that the total number of electrons is the atomic number. Atomic number is represented by the symbol Z.
Mass number is the sum of the number of protons and neutrons inside the nucleus of an atom. This gives the number of subatomic particle present inside the nucleus. Mass number is represented by the symbol A.
From atomic number and mass number, the number of each sub atomic particle can be found.
Complete chemical symbol notation can be given as.
An element is a pure substance that cannot be broken by ordinary chemical reactions into simpler substances. All the atoms in an element will have the same atomic number. The electrons only take part in the chemical reaction while the nucleus does not. Hence, the atomic number (number or protons) does not change and it characterizes an atom.
(b)

Explanation of Solution
Given atom is
Atomic number is given as 78 and mass number is given as 195.
Therefore, the number of protons is 78, number of electrons is 78, and number of neutrons is 117.
The number of protons, electrons and neutrons present in the atom is given.
(c)
Interpretation:
The number of protons, neutrons and electrons present in the atom of
Concept Introduction:
Atomic number for each and every element is a unique one. This is the total number of protons that is present in an atom. As the atom is electrically neutral, it can also be said that the total number of electrons is the atomic number. Atomic number is represented by the symbol Z.
Mass number is the sum of the number of protons and neutrons inside the nucleus of an atom. This gives the number of subatomic particle present inside the nucleus. Mass number is represented by the symbol A.
From atomic number and mass number, the number of each sub atomic particle can be found.
Complete chemical symbol notation can be given as.
An element is a pure substance that cannot be broken by ordinary chemical reactions into simpler substances. All the atoms in an element will have the same atomic number. The electrons only take part in the chemical reaction while the nucleus does not. Hence, the atomic number (number or protons) does not change and it characterizes an atom.
(c)

Explanation of Solution
Given atom is
Atomic number is given as 31 and mass number is given as 72.
Therefore, the number of protons is 31, number of electrons is 31, and number of neutrons is 41.
The number of protons, electrons and neutrons present in the atom is given.
(d)
Interpretation:
The number of protons, neutrons and electrons present in the atom of
Concept Introduction:
Atomic number for each and every element is a unique one. This is the total number of protons that is present in an atom. As the atom is electrically neutral, it can also be said that the total number of electrons is the atomic number. Atomic number is represented by the symbol Z.
Mass number is the sum of the number of protons and neutrons inside the nucleus of an atom. This gives the number of subatomic particle present inside the nucleus. Mass number is represented by the symbol A.
From atomic number and mass number, the number of each sub atomic particle can be found.
Complete chemical symbol notation can be given as.
An element is a pure substance that cannot be broken by ordinary chemical reactions into simpler substances. All the atoms in an element will have the same atomic number. The electrons only take part in the chemical reaction while the nucleus does not. Hence, the atomic number (number or protons) does not change and it characterizes an atom.
(d)

Explanation of Solution
Given atom is
Atomic number is given as 12 and mass number is given as 26.
Therefore, the number of protons is 12, number of electrons is 12, and number of neutrons is 14.
The number of protons, electrons and neutrons present in the atom is given.
Want to see more full solutions like this?
Chapter 3 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Provide an IUPAC name for each of the compounds shown. (Specify (E)/(Z) stereochemistry, if relevant, for straight chain alkenes only. Pay attention to commas, dashes, etc.) H₁₂C C(CH3)3 C=C H3C CH3 CH3CH2CH CI CH3 Submit Answer Retry Entire Group 2 more group attempts remaining Previous Nextarrow_forwardArrange the following compounds / ions in increasing nucleophilicity (least to most nucleophilic) CH3NH2 CH3C=C: CH3COO 1 2 3 5 Multiple Choice 1 point 1, 2, 3 2, 1, 3 3, 1, 2 2, 3, 1 The other answers are not correct 0000arrow_forwardcurved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the cured electron-pushing arrows for thw following reaction or mechanistic steps. be sure to account for all bond-breaking and bond making stepsarrow_forward
- Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.arrow_forwardSynthesis of Dibenzalacetone [References] Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below. Question 1 1 pt Question 2 1 pt Question 3 1 pt H Question 4 1 pt Question 5 1 pt Question 6 1 pt Question 7 1pt Question 8 1 pt Progress: 7/8 items Que Feb 24 at You do not have to consider stereochemistry. . Draw the enolate ion in its carbanion form. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. ⚫ Separate multiple reactants using the + sign from the drop-down menu. ? 4arrow_forwardShown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)arrow_forward
- Hi I need help on the question provided in the image.arrow_forwardDraw a reasonable mechanism for the following reaction:arrow_forwardDraw the mechanism for the following reaction: CH3 CH3 Et-OH Et Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. H± EXP. L CONT. י Α [1] осн CH3 а CH3 :Ö Et H 0 N о S 0 Br Et-ÖH | P LL Farrow_forward
- 20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward20.00 mL of 0.025 M HCl is titrated with 0.035 M KOH. What volume of KOH is needed?arrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning



