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Interpretation:
In the given set of quantum numbers (n, l, ml), the missing quantum numbers should be identified using the concept of quantum numbers.
Concept Introduction:
Each electron in an atom is described by four different quantum numbers. The first three (n, l, ml) specify the particular orbital of interest, and the fourth (ms) specifies how many electrons can occupy that orbital.
Principal Quantum Number (n)
The principal quantum number (n) assigns the size of the orbital and specifies the energy of an electron. If the value of n is larger, then the average distance of an electron in the orbital from the nucleus will be greater. Therefore the size of the orbital is large. The principal quantum numbers have the integral values of 1, 2, 3 and so forth and it corresponds to the quantum number in
The angular momentum quantum number (l) explains the shape of the atomic orbital. The values of l are integers which depend on the value of the principal quantum number, n. For a given value of n, the possible values of l range are from 0 to n − 1. If n = 1, there is only one possible value of l (l=0). If n = 2, there are two values of l: 0 and 1. If n = 3, there are three values of l: 0, 1, and 2. The value of l is selected by the letters s, p, d, and f. If l = 0, we have an s orbital; if l = 1, we have a p orbital; if l = 2, we have a d orbital and finally if l = 3, we have a f orbital. A collection of orbitals with the same value of n is called a shell. One or more orbitals with the same n and l values are referred to a subshell (sublevel). The value of l also has a slight effect on the energy of the subshell; the energy of the subshell increases with l (s < p < d < f).
Magnetic Quantum Number (ml)
The magnetic quantum number (ml) explains the orientation of the orbital in space. The value of ml depends on the value of l in a subshell. This number divides the subshell into individual orbitals which hold the electrons. For a certain value of l, there are (2l + 1) integral values of ml which is explained as follows:
ml = ‒ l, ..., 0, ..., +l
If l = 0, there is only one possible value of ml: 0.
If l = 1, then there are three values of ml: −1, 0, and +1.
If l = 2, there are five values of ml, namely, −2, −1, 0, +1, and +2.
If l = 3, there are seven values of ml, namely, −3, −2, −1, 0, +1, +2, and +3, and so on.
The number of ml values indicates the number of orbitals in a subshell with a particular l value. Therefore, each ml value refers to a different orbital.
To find: Get the missing quantum numbers in the given set of quantum numbers (n, l, ml)
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Chapter 3 Solutions
Chemistry: Atoms First
- Add curved arrows to the reactants in this reaction. A double-barbed curved arrow is used to represent the movement of a pair of electrons. Draw curved arrows. : 0: si H : OH :: H―0: Harrow_forwardConsider this step in a radical reaction: Br N O hv What type of step is this? Check all that apply. Draw the products of the step on the right-hand side of the drawing area below. If more than one set of products is possible, draw any set. Also, draw the mechanism arrows on the left-hand side of the drawing area to show how this happens. O primary Otermination O initialization O electrophilic O none of the above × ☑arrow_forwardNonearrow_forward
- Can I get a drawing of what is happening with the orbitals (particularly the p orbital) on the O in the OH group? Is the p orbital on the O involved in the ring resonance? Why or why not?arrow_forward1) How many monochlorination products-including stereochemistry- are there for the molecule below:arrow_forwardSelect an amino acid that has and N-H or O-H bond in its R-group (you have 8 to choose from!). Draw at least two water molecules interacting with the R-group of the amino acid.arrow_forward
- Is this aromatic?arrow_forwardCHEM2323 E Tt PS CH03 Draw and name all monobromo derivatives of pentane, C5H11Br. Problem 3-33 Name: Draw structures for the following: (a) 2-Methylheptane (d) 2,4,4-Trimethylheptane Problem 3-35 (b) 4-Ethyl-2,2-dimethylhexane (e) 3,3-Diethyl-2,5-dimethylnonane (c) 4-Ethyl-3,4-dimethyloctane 2 (f) 4-Isopropyl-3-methylheptane KNIE>arrow_forwardProblem 3-42 Consider 2-methylbutane (isopentane). Sighting along the C2-C3 bond: (a) Draw a Newman projection of the most stable conformation. (b) Draw a Newman projection of the least stable conformation. Problem 3-44 Construct a qualitative potential-energy diagram for rotation about the C-C bond of 1,2-dibromoethane. Which conformation would you expect to be most stable? Label the anti and gauche conformations of 1,2- dibromoethane. Problem 3-45 Which conformation of 1,2-dibromoethane (Problem 3-44) would you expect to have the largest dipole moment? The observed dipole moment of 1,2-dibromoethane is µ = 1.0 D. What does this tell you about the actual conformation of the molecule?arrow_forward
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