UNDERSTANDING THE UNIVERSE(LL)-W/CODE
3rd Edition
ISBN: 9780393869903
Author: PALEN
Publisher: NORTON
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Chapter 3, Problem 35QAP
To determine
The reason for spaceports to be located near equator and reason for satellites to never launched toward west.
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Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem:
mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2
1.)Which of the following quantities would change the radius the satellite needs to orbit at?
a.)the mass of the satellite
b.)the mass of the planet
c.)the speed of the satellite
2.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem:
mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2
1.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?
A typical adult human has a mass of about 70 kg. (a) What force does a full moon exert on such a human when it is directly overhead with its center 378,000 km away? (b) Compare this force with the force exerted on the human by the earth.
Chapter 3 Solutions
UNDERSTANDING THE UNIVERSE(LL)-W/CODE
Ch. 3.1 - Prob. 3.1CYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3.5 - Prob. 3.5CYUCh. 3 - Prob. 1QAPCh. 3 - Prob. 2QAPCh. 3 - Prob. 3QAPCh. 3 - Prob. 4QAPCh. 3 - Prob. 5QAP
Ch. 3 - Prob. 6QAPCh. 3 - Prob. 7QAPCh. 3 - Prob. 8QAPCh. 3 - Prob. 9QAPCh. 3 - Prob. 10QAPCh. 3 - Prob. 11QAPCh. 3 - Prob. 12QAPCh. 3 - Prob. 13QAPCh. 3 - Prob. 14QAPCh. 3 - Prob. 15QAPCh. 3 - Prob. 16QAPCh. 3 - Prob. 17QAPCh. 3 - Prob. 18QAPCh. 3 - Prob. 19QAPCh. 3 - Prob. 20QAPCh. 3 - Prob. 21QAPCh. 3 - Prob. 22QAPCh. 3 - Prob. 23QAPCh. 3 - Prob. 24QAPCh. 3 - Prob. 25QAPCh. 3 - Prob. 26QAPCh. 3 - Prob. 27QAPCh. 3 - Prob. 28QAPCh. 3 - Prob. 29QAPCh. 3 - Prob. 30QAPCh. 3 - Prob. 31QAPCh. 3 - Prob. 32QAPCh. 3 - Prob. 33QAPCh. 3 - Prob. 34QAPCh. 3 - Prob. 35QAPCh. 3 - Prob. 36QAPCh. 3 - Prob. 37QAPCh. 3 - Prob. 38QAPCh. 3 - Prob. 39QAPCh. 3 - Prob. 40QAPCh. 3 - Prob. 41QAPCh. 3 - Prob. 42QAPCh. 3 - Prob. 43QAPCh. 3 - Prob. 44QAPCh. 3 - Prob. 45QAP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A planet has two moons with identical mass. Moon 1 is in a circular orbit of radius r. Moon 2 is in a circular orbit of radius 2r. The magnitude of the gravitational force exerted by the planet on Moon 2 is (a) four times as large (b) twice as large (c) the same (d) half as large (e) one-fourth as large as the gravitational force exerted by the planet on Moon 1.arrow_forwardA planet has two moons of equal mass. Moon 1 is in a circular orbit of radius r. Moon 2 is in a circular orbit of radius 2r. What is the magnitude of the gravitational force exerted by the planet on Moon 2? (a) four times as large as that on Moon 1 (b) twice as large as that on Moon 1 (c) equal to that on Moon 1 (d) half as large as that on Moon 1 (e) one-fourth as large as that on Moon 1arrow_forwardIt was stated that a satellite with negative total energy is in a bound orbit, whereas one with zero or positive total energy is in an unbounded orbit. Why zero or positive total energy is in an unbounded orbit. Why is this true? What choice for gravitational potential energy was made such that this is true?arrow_forward
- Let gM represent the difference in the gravitational fields produced by the Moon at the points on the Earths surface nearest to and farthest from the Moon. Find the fraction gM/g, where g is the Earths gravitational field. (This difference is responsible for the occurrence of the lunar tides on the Earth.)arrow_forwardCalculate the mass of the Sun based on data for average Earth’s orbit and compare the value obtained with the Sun’s commonly listed value of 1.9891030kg .arrow_forwardA satellite is put in a circular orbit about Earth with a radius equal to one-half the radius of the Moon’s orbit.What is its period of revolution in lunar months? (A lunar month is the period of revolution of the Moon.)arrow_forward
- The Moon has no atmosphere so there is no reason for satellites to orbit very high above it. The highest mountain on the Moon is Mons Hadley at 4.5 km above the lunar surface. If a satellite was orbiting the Moon at an altitude of 4.51 km, how fast would it need to be moving to stay in orbit? You can find data about the Moon in the back endpapers of the textbook or just google what you need.arrow_forwardAn orbiting satellite stays over a certain spot on the equator of (rotating) Earth.What is the altitude of the orbit (called a geosynchronous orbit)?arrow_forwardA satellite orbits in the equatorial plane so that it is always above the same point of Earth's surface. How far away is it from the center of Earth? (The solution is 42.3×10^6 m)arrow_forward
- The mass of planet Q is one-tenth of the mass of Earth and the radius of planet Q is one-half of the radius of Earth. (a)Use this information to calculate the gravitational field at the surface of Q.(The gravitational field at the surface of Earth is 9.8 N/kg)(b) What is the escape velocity for Q? (The escape velocity for Earth is 11,200m/s.)arrow_forwardLet's say an apple weighs exactly 1N on the surface of the Earth (which corresponds to a distance of 6400 km from the center of the Earth). Now imagine an astronaut brings the apple on a spaceship. What is the force of the Earth's gravity on this apple at a vertical distance of 6400 km above the surface of the Earth? Hint: the radial distance of the apple from the center has doubled. What does this do to the force of gravity according to Newton's law of universal gravitation?arrow_forwardNewton's Law of Gravitation can be used to show that if an object weighs w pounds on the surface of the earth, then its weight at a distance x from the center of the earth is W(x) : wR? (for x > R), where R = 3960 miles is the radius of the earth. Estimate the weight loss per mile of altitude gained for a 205-lb pilot at an altitude of h. (Use decimal notation. Give your answer to five decimal places.)arrow_forward
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