(a)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(a)
Answer to Problem 34PP
Explanation of Solution
The most acidic proton of the given acid (a) is
(b)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(b)
Answer to Problem 34PP
Explanation of Solution
The most acidic hydrogen atom presented in the given acid is
.
No other
(c)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(c)
Answer to Problem 34PP
Explanation of Solution
Deprotonation of
(d)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(d)
Answer to Problem 34PP
Explanation of Solution
Deprotonation of
(e)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(e)
Answer to Problem 34PP
Explanation of Solution
The most acidic proton of the given acid (e) is
(f)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(f)
Answer to Problem 34PP
Explanation of Solution
The most acidic proton of the given acid (e) is
(g)
Interpretation:
Conjugate bases of given acids are needed to be drawn.
Concept introduction:
According to Bronsted-Lowry concept, acid is a proton donor. The deprotonated acids are called conjugate base. The stability of this conjugate base determines the location of deprotonation in an acid.
In a conjugate base where the negative charge is carried by a more electronegative atom will show more stability. The greater electronegativity makes lone pair closer to the nucleus hence more stabilized.
The conjugate base having resonance will have greater stability as compared to conjugate base having single anion. Because of the resonance conjugate base will get resonance stabilization.
(g)
Answer to Problem 34PP
Explanation of Solution
Deprotonation of
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Chapter 3 Solutions
ORGANIC CHEMISTRYPKGDRL+MLCRL MDL
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- 9. Which one of the following substituents is the worst leaving group inan SN2 reaction? A. -NH2; B. -OH; C. –F; D. NH3; E. H2O Please include all steps. Thanks!arrow_forwardUsing the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 2.5 × 105: CO(g) + H2O(g) CO2(g) + H2(g) Use this information to complete the following table. Suppose a 7.0 L reaction vessel is filled with 1.7 mol of CO and 1.7 mol of H2O. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. CO2(9)+H2(g) CO(g)+H₂O(g) What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 3 CO(g)+3H2O(g) = 3 CO2(g)+3H2(g) There will be very little CO and H2O. x10 There will be very little CO2 and H2. 000 Neither of the above is true. K = ☐ K = ☐ 18 Ararrow_forward8. When ethane thiol is treated with hydrogen peroxide the product is___.A. ethane disulfide; B. diethyl sulfide; C. ethane sulfoxide; D. ethanesulfate; E. ethyl mercaptan. Please include all steps. Thanks!arrow_forward
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