The answer for the given problem has to be written with correct number of significant figures. 1.0 + 2.1 + 3.4 + 5.8 = 12.3000 Concept Introduction: Significant Figures: While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures. All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Question

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Answer 1

Question

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Expert Solution & Answer

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Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF solution. bases: Х other: ☐ acids: 0.10 mol of HI is added to 1.0 L of a solution that is 1.4M in both HF and NaF. bases: other: ☐ 0,0,... ด ? 18 Ar

Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that NH3 is a weak base. acids: ☐ 1.8 mol of HCl is added to 1.0 L of a 1.0M NH3 bases: ☐ solution. other: ☐ 0.18 mol of HNO3 is added to 1.0 L of a solution that is 1.4M in both NH3 and NH₁Br. acids: bases: ☐ other: ☐ 0,0,... ? 000 18 Ar B 1

Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NH3 (g) = N2 (g) +3H₂ —N2 (g) AGº = 34. kJ Now suppose a reaction vessel is filled with 4.19 atm of ammonia (NH3) and 9.94 atm of nitrogen (N2) at 378. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NH 3 tend to rise or fall? ☐ x10 fall Х Is it possible to reverse this tendency by adding H₂? In other words, if you said the pressure of NH 3 will tend to rise, can that be changed to a tendency to fall by adding H₂? Similarly, if you said the pressure of NH3 will tend to fall, can that be changed to a tendency to rise by adding H₂? If you said the tendency can be reversed in the second question, calculate the minimum pressure of H₂ needed to reverse it. Round your answer to 2 significant digits. yes no atm 00. 18 Ar 무ㅎ ?

Answer 2

Question

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Expert Solution & Answer

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Answer 3

Question

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Answer 6

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Answer 7

Chapter 3, Problem 3.4P

(a)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

1.0+2.1+3.4+5.8=12.3000

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

Answer 10

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

Answer 11

(c)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

Answer 12

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

Answer 13

(d)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

Answer 14

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

Answer 15

(e)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

Answer 16

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

Answer 17

(f)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

Answer 18

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

Answer 19

(g)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

log (3.98×104) = 4.599 9

Concept Introduction:

Significant Figures:

While reporting a reading of a measurement, the digits that are considered to be significant irrespective of the place of location of decimal point are called significant figures.

All the digits in a measurement except zero are considered significant, whereas zero is considered as significant only when it lies in the middle of the digit or at the end of number on the right-hand side of a decimal point.

Logarithms and Antilogarithms:

For logarithms,

Number of digits in matissa of log x = number of significant figure in x

For antilogarithms,

Number of digits in antilog x (=10x)=number of significant figures in mantissa of x

Answer 20

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Answer 21

(h)

Interpretation Introduction

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Answer 22

Expert Solution & Answer

Answer 23

Expert Solution & Answer

Answer 24

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Check out a sample textbook solution

See solution

Answer 25

Ch. 3 - Prob. 3.1P Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - Prob. 3.4P Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.10P Ch. 3 - Prob. 3.11P

Concept explainers

Videos

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).

Want to see the full answer?

Chapter 3 Solutions

Concept explainers

Videos

Interpretation: The answer for the given problem has to be written with correct number of significant figures. 106.9−31.4=75.5000 Concept Introduction: Refer part (a).

Interpretation: The answer for the given problem has to be written with correct number of significant figures. 107.88−(2.113×102)+(5.623×103)=5519.568 Concept Introduction: Refer part (a).

Interpretation: The answer for the given problem has to be written with correct number of significant figures. (26.14/37.62)×4.38=3.043413 Concept Introduction: Refer part (a).

Interpretation: The answer for the given problem has to be written with correct number of significant figures. (26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10 Concept Introduction: Refer part (a).

Interpretation: The answer for the given problem has to be written with correct number of significant figures. (26.14/3.38)+4.2=11.9337 Concept Introduction: Refer part (a).

Interpretation: The answer for the given problem has to be written with correct number of significant figures. 10−6.31 = 4.89779×10−7 Concept Introduction: Refer part (g).

Want to see the full answer?

Chapter 3 Solutions

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

106.9−31.4=75.5000

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

107.88−(2.113×102)+(5.623×103)=5519.568

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/37.62)×4.38=3.043413

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/(37.62×108))×(4.38×10−2)=3.043413×10−10

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

(26.14/3.38)+4.2=11.9337

Concept Introduction:

Refer part (a).

Interpretation:

The answer for the given problem has to be written with correct number of significant figures.

10−6.31 = 4.89779×10−7

Concept Introduction:

Refer part (g).