EXPLOR. CHEM ANALYSIS (LL) - W/ ACHIEVE
EXPLOR. CHEM ANALYSIS (LL) - W/ ACHIEVE
5th Edition
ISBN: 9781319468859
Author: Harris
Publisher: MAC HIGHER
Question
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Chapter 3, Problem 3.11P

(a)

Interpretation Introduction

Interpretation:

The absolute and percent relative uncertainty with a reasonable number of significant figures has to be found out for 6.2(±0.2)4.1(±0.1)=?

Concept Introduction:

Uncertainty:

Uncertainty means state of not certain in predicting a value.  In a measured value, the last digit will have associated uncertainty. Uncertainty has two values, absolute uncertainty and relative uncertainty.

Absolute uncertainty:

  Expressed the marginal value associated with a measurement

Relative uncertainty:

Compares the size of absolute uncertainty with the size of its associated measurement

  Relative uncertainty = absolute uncertaintymagnitude of measurement

For a set measurements having uncertainty values as e1,e2 and e3, the uncertainty (e4) in addition and subtraction can be calculated as follows,

  e4=e12+e22+e32

Percent relative uncertainty:

  Percent relative uncertainty = 100 × relative uncertainty

(b)

Interpretation Introduction

Interpretation:

The absolute and percent relative uncertainty with a reasonable number of significant figures has to be found out for 9.43(±0.05)×0.016(±0.001)=?

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

The absolute and percent relative uncertainty with a reasonable number of significant figures has to be found out for [6.2(±0.2)4.1(±0.1)]÷9.43(±0.05)=?.

Concept Introduction:

Refer part (a).

(d)

Interpretation Introduction

Interpretation:

The absolute and percent relative uncertainty with a reasonable number of significant figures has to be found out for 9.43(±0.05)×{[6.2(±0.2)×103]+[4.1(±0.1)×103]}=?.

Concept Introduction:

Refer part (a).

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