Essentials of Computer Organization and Architecture
Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
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Chapter 3, Problem 34E
Program Plan Intro

a.

K-Map:

  • K-Map stands for Karnaugh Map which is used to reduce the logic functions more easily and quickly.
  • It will minimize the Boolean expressions without using Boolean algebra theorems.
  • By using K-Map, the Boolean expressions with two to four variables are easily reduced.

Expert Solution
Check Mark

Explanation of Solution

Simplification of Boolean expression using K-Map:

 Given:

 F(x, y, z)=w'x'y'z + w'x'yz' + w'xy'z +   w'xyz  + w'xyz' +  wxy'z +   wxyz + wx'y'z

 The K-Map for the given expression is as follows:

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  1

 The following steps are used to obtain the simplified Boolean expressions.

 Step1:

 Then group another possible 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  2

 F = w'x'y'z + w'xy'z + wxy'z + wx'y'z= w'y'z(x'+x) + wy'z(x'+x)=w'y'z(1) + wy'z(1)=w'y'z + wy'z

    =(w' + w)y'z=(1)y'z=y'z

 Step2:

  The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  3

 F = w'xy'z + w'xyz + wxy'z + wxyz= w'xz(y'+y) + wxz(y'+y)=w'xz(1) + wxz(1)=w'xz + wxz

    =(w' + w)xz=(1)xz=xz

 Step3:

  The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  4

 F = w'x'yz' + w'xyz'= w'yz'(x' + x)=w'yz'(1)=w'yz'

 Step4:

 Group all the expressions

 F = y'z + xz + w'yz'

 Therefore, the simplified expression is “F = y'z + xz + w'yz'”.

Program Plan Intro

b.

K-Map:

  • K-Map stands for Karnaugh Map which is used to reduce the logic functions more easily and quickly.
  • It will minimize the Boolean expressions without using Boolean algebra theorems.
  • By using K-Map, the Boolean expressions with two to four variables are easily reduced.

Expert Solution
Check Mark

Explanation of Solution

Simplification of Boolean expression using K-Map:

 Given:

 F(x, y, z)=w'x'y'z' + w'z + w'x'yz' + w'xy'z' + wx'y

 Simplifying the given equation into 4 variable terms as shown below:

 F(x, y, z)=w'x'y'z' + w'z + w'x'yz' + w'xy'z' + wx'y=w'x'y'z' + w'z(x' + x)(y' + y) + w'x'yz' +   w'xy'z' + wx'y(z' + z)=w'x'y'z' + w'z(x'y' + x'y + xy' + xy)+ w'x'yz' +

                   w'xy'z' + wx'yz' + wx'yz= w'x'y'z' + w'x'y'z + w'x'yz +  w'xy'z + w'xyz + w'x'yz' +  w'xy'z' + wx'yz' + wx'yz

 The K-Map for the given expression is as follows:

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  5

 The following steps are used to obtain the simplified Boolean expressions.

 Step1:

 The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  6

 F = w'x'y'z' + w'x'y'z + w'xy'z' + w'xy'z= w'x'y'(z' + z)+ w'xy'(z' + z)=w'x'y'(1)+ w'xy'(1)=w'x'y'+ w'xy'

    =(x' + x)w'y'=(1)w'y'=w'y'

 Step2:

 The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  7

 F = w'x'y'z + w'x'yz + w'xy'z + w'xyz= w'x'z(y' + y)+ w'xz(y' + y)=w'x'z(1)+ w'xz(1)=w'x'z+ w'xz

    =(x' + x)w'z=(1)w'z=w'z

 Step3:

 The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  8

 F = w'x'yz + w'x'yz' + wx'yz + wx'yz'= w'x'y(z' + z)+ wx'y(z' + z)=w'x'y(1)+ wx'y(1)=w'x'y+ wx'y

    =(w' + w)x'y=(1)x'y=x'y

 Step4:

 Group all the expressions

 F = w'y' + w'z + x'y

 Therefore, the simplified expression is “F = w'y' + w'z + x'y”.

Program Plan Intro

c.

K-Map:

  • K-Map stands for Karnaugh Map which is used to reduce the logic functions more easily and quickly.
  • It will minimize the Boolean expressions without using Boolean algebra theorems.
  • By using K-Map, the Boolean expressions with two to four variables are easily reduced.

Expert Solution
Check Mark

Explanation of Solution

Simplification of Boolean expression using K-Map:

 Given:

 F(x, y, z)=w'x'y' + w'xz + wxz + wx'y'z'

 Simplifying the given equation into 4 variable terms as shown below:

 F(x, y, z)=w'x'y' + w'xz + wxz + wx'y'z'=w'x'y'(z' + z) + w'xz(y' + y) +   wxz(y' + y) + wx'y'z'=w'x'y'z' + w'x'y'z +w'xy'z + w'xyz

                     + wxy'z + wxyz + wx'y'z'

 The K-Map for the given expression is as follows:

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  9

 The following steps are used to obtain the simplified Boolean expressions.

 Step1:

 Then group another possible 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  10

 F = w'xy'z+ w'xyz+ wxy'z+ wxyz= w'xz(y + y') + wxz(y + y')=w'xz(1) + wxz(1)=xz(w' + w)

    =xz(1)=xz

 Step2:

 The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  11

 F = w'x'y'z+ w'x'y'z'= w'x'y'(z + z')=w'x'y'(1)=w'x'y'

 Step3:

 The group the 1’s in the table. Then write the Boolean expression according to the mapping. Write 0 term’s as complemented variable like x’ and 1 term’s as it is like x.

Essentials of Computer Organization and Architecture, Chapter 3, Problem 34E , additional homework tip  12

 F = w'x'y'z'+ wx'y'z'= x'y'z'(w' + w)=x'y'z'(1)=x'y'z'

 Step4:

 Group all the expressions

 F = w'x'y' + xz + x'y'z'

 Therefore, the simplified expression is “F = w'x'y' + xz + x'y'z'”.

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Chapter 3 Solutions

Essentials of Computer Organization and Architecture

Ch. 3 - Prob. 11RETCCh. 3 - Prob. 12RETCCh. 3 - Prob. 13RETCCh. 3 - Prob. 14RETCCh. 3 - Prob. 15RETCCh. 3 - Prob. 16RETCCh. 3 - Prob. 17RETCCh. 3 - Prob. 18RETCCh. 3 - Prob. 19RETCCh. 3 - Prob. 20RETCCh. 3 - Prob. 21RETCCh. 3 - Prob. 22RETCCh. 3 - Prob. 23RETCCh. 3 - Prob. 24RETCCh. 3 - Prob. 25RETCCh. 3 - Prob. 26RETCCh. 3 - Prob. 1ECh. 3 - Prob. 2ECh. 3 - Prob. 3ECh. 3 - Prob. 4ECh. 3 - Prob. 5ECh. 3 - Prob. 6ECh. 3 - Prob. 7ECh. 3 - Prob. 8ECh. 3 - Prob. 9ECh. 3 - Prob. 10ECh. 3 - Prob. 11ECh. 3 - Prob. 12ECh. 3 - Prob. 13ECh. 3 - Prob. 14ECh. 3 - Prob. 15ECh. 3 - Prob. 16ECh. 3 - Prob. 17ECh. 3 - Prob. 18ECh. 3 - Prob. 19ECh. 3 - Prob. 20ECh. 3 - Prob. 21ECh. 3 - Prob. 22ECh. 3 - Prob. 23ECh. 3 - Prob. 24ECh. 3 - Prob. 25ECh. 3 - Prob. 26ECh. 3 - Prob. 27ECh. 3 - Prob. 28ECh. 3 - Prob. 29ECh. 3 - Prob. 30ECh. 3 - Prob. 31ECh. 3 - Prob. 32ECh. 3 - Prob. 33ECh. 3 - Prob. 34ECh. 3 - Prob. 35ECh. 3 - Prob. 36ECh. 3 - Prob. 37ECh. 3 - Prob. 38ECh. 3 - Prob. 39ECh. 3 - Prob. 40ECh. 3 - Prob. 41ECh. 3 - Prob. 42ECh. 3 - Prob. 43ECh. 3 - Prob. 44ECh. 3 - Prob. 45ECh. 3 - Prob. 46ECh. 3 - Prob. 47ECh. 3 - Prob. 48ECh. 3 - Prob. 49ECh. 3 - Prob. 50ECh. 3 - Prob. 51ECh. 3 - Prob. 52ECh. 3 - Prob. 53ECh. 3 - Prob. 54ECh. 3 - Prob. 55ECh. 3 - Prob. 56ECh. 3 - Prob. 57ECh. 3 - Prob. 58ECh. 3 - Prob. 59ECh. 3 - Prob. 60ECh. 3 - Prob. 61ECh. 3 - Prob. 62ECh. 3 - Prob. 63ECh. 3 - Prob. 64ECh. 3 - Prob. 65ECh. 3 - Prob. 66ECh. 3 - Prob. 67ECh. 3 - Prob. 68ECh. 3 - Prob. 70ECh. 3 - Prob. 71ECh. 3 - Prob. 72ECh. 3 - Prob. 73ECh. 3 - Prob. 74ECh. 3 - Prob. 75ECh. 3 - Prob. 76ECh. 3 - Prob. 77ECh. 3 - Prob. 78ECh. 3 - Prob. 79ECh. 3 - Prob. 80E
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