Principles of Foundation Engineering, SI Edition
8th Edition
ISBN: 9781305446298
Author: Braja M. Das
Publisher: Cengage Learning US
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Question
Chapter 3, Problem 3.1P
To determine
Find the area ratio of the Shelby tube.
Expert Solution & Answer
Answer to Problem 3.1P
The area ratio of the tube is
Explanation of Solution
Given information:
The outside diameter
The inside diameter
Calculation:
Calculate the area ratio
Therefore, the area ratio of the tube is
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A simply supported rectangular RC beam is to carry a uniform factored dead load of 1.2 kip/ft
and a concentrated factored live load of 16 kip at mid-span. The beam self-weight is not included
in these loads. The concrete weighs 135 pcf. The span length is 25 ft. Please find the smallest
section allowed by ACI and design accordingly. Use f c’ = 5,000 psi, f y = 75,000 psi. The
exposure is interior with no weather exposure.
a. Assume an arbitrary self-weight/ft of the beam.
b. Find the maximum factored bending moment in the beam.
c. Set up the moment equation and solve for the beam section.
d. Revise the assumption if needed
Ideal gas
Problems
3-1 The molecular weight of carbon dioxide, CO2, is 44. In an experiment the value y for
CO2 was found to be 1.3. Assuming that CO2 is a perfect gas, calculate the gas
constant, R, and the specific heats at constant pressure and constant volume, Cp, Cv
(0.189 kJ/kg.K; 0.63kJ/kg.K; 0.819kJ/kg.K)
3-2 Oxygen, O2, at 200 bar is to be stored in a steel vessel at 20°C the capacity of the vessel
is 0.04m³. Assuming that O₂ is a perfect gas, calculate the mass of oxygen that can be
stored in the vessel. The vessel is protected against excessive pressure by a fusible plug
which will melt if the temperature rises too high. At what temperature must the plug
melt to limit the pressure in the vessel to 240bar? The molecular weight of oxygen is 32
(10.5 kg; 78.6°C)
3-3 A quantity of a certain perfect gas is compressed from an initial state of 0.085m³, 1 bar
to a final state of 0.034m³, 3.9 bar. The specific heats at constant volume are 0.724
kJ/kg.K, and the specific heats at…
Chapter 3 Solutions
Principles of Foundation Engineering, SI Edition
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Refer to Figure P3.3. Use Eqs. (3.10) and (3.11)...Ch. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Following are the standard penetration numbers...Ch. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27P
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