Principles Of Geotechnical Engineering, Si Edition
9th Edition
ISBN: 9781305970953
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 3, Problem 3.15P
(a)
To determine
Calculate the mass of water to be added per cubic meter of soil.
(b)
To determine
Calculate the mass of water to be added per cubic meter of soil.
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The bolted connection shown is connected with
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A 3.048 m long column (Fy = 483 MPa) carries an axial compression load of 5000 kN dead load. The column is braced at mid-height to strengthen the column in the weak direction. Use LRFD.
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When an open-ended square tube is placed vertically into a pool of water, the water rises 4 mm
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Chapter 3 Solutions
Principles Of Geotechnical Engineering, Si Edition
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - For a given sandy soil, emax = 0.75 and emin =...Ch. 3 - For a given sandy soil, the maximum and minimum...Ch. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.1CTPCh. 3 - Prob. 3.2CTPCh. 3 - Prob. 3.3CTP
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- 11. Design the main beam of a building supporting concrete floor slab as shown in Fig. 10.61 and with the following data: (i) Beam centres: 6 m (ii) Span (simply supported): 7.4 m (iii) Concrete slab (spanning in two directions): 240-mm thick (iv) Finished screed: 40-mm thick (v) Imposed load: 4 kN/m² (vi) Take weight of concrete slab as 24 kN/m³ and total weight of 40-mm thick screed as 1.0 kN/m² Assume Fe 410 grade steel and take initial weight of beam as 1.0 kN/m. H H- Main beam 7.4 m 6.0 m H 40 mm screed I -H. Fig. 10.61 k 240 mm slab 6.0 m Typical bay of large floor areaarrow_forwardConsider the situation in Question 2. If all the cables are made of the same material and have a maximum tensile force of 500 lb, what is the heaviest load that can be supported by the system?arrow_forwardA flexible circular area is subjected to a uniformly distributed load of 148 (see the figure below). The diameter of the load area is 2 . Estimate the average stress increase () below the center of the loaded area between depths of 3 and 6 . Use the equations: and (Enter your answer to three significant figures.) =arrow_forward
- A square flexible foundation of width B applies a uniform pressure go to the underlying ground. (a) Determine the vertical stress increase at a depth of 0.625B below the center using Aσ beneath the corner of a uniform rectangular load given by Aσ = Variation of Influence Value I qoI. Use the table below. n 0.8 1.0 m 0.2 0.4 0.5 0.6 0.2 0.01790 0.03280 0.03866 0.04348 0.05042 0.05471 0.4 0.03280 0.06024 0.07111 0.08009 0.09314 0.10129 0.5 0.03866 0.07111 0.08403 0.09473 0.11035 0.12018 0.6 0.04348 0.08009 0.09473 0.10688 0.12474 0.13605 0.8 0.05042 0.09314 0.11035 0.12474 0.14607 0.15978 1.0 0.05471 0.10129 0.12018 0.13605 0.15978 0.17522 (Enter your answer to three significant figures.) Ασ/90 = (b) Determine the vertical stress increase at a depth of 0.625B below the center using the 2 : 1 method equation below. 90 x B x L Aσ = (B+ z) (L + z) (Enter your answer to three significant figures.) Ασ/90 = (c) Determine the vertical stress increase at a depth of 0.625B below the center using…arrow_forwardPoint loads of magnitude 100, 200, and 360 act at , , and , respectively (in the figure below). Determine the increase in vertical stress at a depth of 6 below point . Use Boussinesq's equation. (Enter your answer to three significant figures.) =arrow_forwardno chatgpt, show solution. thx^^arrow_forward
- P 20 mm 15 mm 100 mm 200 mm 100 mm 15 mm -450.0 mm- -300.0 mm 300.0 mm -300.0 mm -450.0 mm- 300.0 mm The butt connection shows 8-24mm bolts. Spacing and dimensions are shown in figure PSAD-020. The plate is made of A36 steel. Allowable tensile stress on gross area = 0.6Fy Allowable tensile stress on net area = 0.5Fu Allowable shear stress on net area = 0.3Fu Bolt hole diameter = 26mm Determine the allowable tensile load P based on net area rupture. Determine the allowable tensile load P based on gross area yielding. Determine the allowable tensile load P based on block shear strength. Parrow_forward300 mm P 75 mm -75 mm P I 75 mm 100 mm -125 mm Shown in figure PSAD-022 is a splice connection made of 8-22mm A325 bolts and a PL 300 x 12 mm made of A36 steel, connected back-to-back. The connection joins together two A992 W410X67 (Fy = 50 ksi, Fu = 65 ksi) carrying a tension load P. Assume U = 0.70. Ignore bolt shear failure. Determine the design capacity of the connection based on yielding of the plate. Determine the design capacity of the section based on yielding of the wide flange section. Determine the design capacity of the section based on rupture of the plate. Determine the design capacity of the section based on block shear of the plate.arrow_forwardProperties of L 152 x 152 x 11.1 A = 3280 mm² d = 152 mm t = 11.1 mm x = 41.9 mm Ix=7.33 x 10 mm⭑ Iy = 7.33 x 10 mm Zx=119 x 103 mm³ Sx = 66.5 x 103 mm³ P ° ° ° ° ° ° ° ° P Shown in figure PSAD-021 is a truss joint detail. It makes use of two rows of 22-mm bolts. The members are L 152 x 152 x 11.1 made of A36. The plate connecting the members is a 9mm-thick A36 plate (Fy = 36 ksi, Fu = 58 ksi). Assume that U = 0.85, ignore 85% limit of net area. Determine the effective net area of the section. Determine the allowable capacity of the connection.arrow_forward
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