Process Dynamics And Control, 4e
Process Dynamics And Control, 4e
16th Edition
ISBN: 9781119385561
Author: Seborg, Dale E.
Publisher: WILEY
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Chapter 3, Problem 3.15E
Interpretation Introduction

Interpretation:

The solution of the given differential equation is to be determined. Also, the graph of the solution for the given conditions are to be plotted.

Concept introduction:

For a function f(t), the Laplace transform is given by,

F(s)=L[f(t)]=0f(f)estdt ..... (1)

Here, F(s) represents the Laplace transform, s is a variable which is complex and independent, f(t) is any function of time which is being transformed, and L is the operator which is defined by an integral.

f(t) is calculated by taking inverse Laplace transform of the function F(s).

PFE is the partial fraction expansion is the method of expanding the denominator of a fraction into simpler terms.

Laplace transform of higher order derivatives is given by:

L(dnfdtn)=snF(s)sn1f(0)sn2f(1)(0)sf(n2)(0)f(n1)(0) ..... (2)

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please... please. , how can I use the boundary conditions for this question (two fixed pates and the distance between plates is h).
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Assignment 2. Example. The diffusivity of the vapour of a volatile liquid in air can be conveniently determined by Winkelmann's method in which liquid is contained in a narrow diameter vertical tube, maintained at a constant temperature, and an air stream is passed over the top of the tube sufficiently rapidly to ensure that the partial pressure of the vapour there remains approximately zero. On the assumption that the vapour is transferred from the surface of the liquid to the air stream by molecular diffusion, calculate the diffusivity of carbon tetrachloride vapour in air at 321 K and atmospheric pressure from the following experimental data: Time from commencement of experiment, (t x1 03 s) Liquid level (mm) 0.0 0.0 1.6 2.5 11.1 12.9 27.4 23-2 80-2 43.9 117.5 54-7 168.6 67.0 199.7 73-8 289-3 90-3 383-1 104.8 The vapour pressure of carbon tetrachloride at 321 K is 37.6 kN/m² and the density of the liquid is 1540 kg/m³. Take the kilogram molecular volume as 22.4 m³.
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