Two infinite extent current sheets exist at z = − 2.0 m and at z = + 2.0 m . The top sheet has a uniform current density K = 3.0 a y A / m and the bottom one has K = − 3.0 a y A / m . Find H at (a) ( 0 , 0 , 4 m ) , (b) ( 0 , 0 , 0 ) , and (c) ( 0 , 0 , − 4 m ) .
Two infinite extent current sheets exist at z = − 2.0 m and at z = + 2.0 m . The top sheet has a uniform current density K = 3.0 a y A / m and the bottom one has K = − 3.0 a y A / m . Find H at (a) ( 0 , 0 , 4 m ) , (b) ( 0 , 0 , 0 ) , and (c) ( 0 , 0 , − 4 m ) .
Solution Summary: The author calculates the magnetic field intensity at the point due to the two sheets of charge.
Two infinite extent current sheets exist at
z
=
−
2.0
m
and at
z
=
+
2.0
m
. The top sheet has a uniform current density
K
=
3.0
a
y
A
/
m
and the bottom one has
K
=
−
3.0
a
y
A
/
m
. Find H at (a)
(
0
,
0
,
4
m
)
, (b)
(
0
,
0
,
0
)
, and (c)
(
0
,
0
,
−
4
m
)
.
I need a drawing on how to connect the function generator, oscilliscope, and both multimeters. It is hard for me to follow text instructions. The function generator has a postive,common and negative. The oscilliscope has chanell A and B, both channels have a postive and a negative. I know you can provide text instruction but a little sketch would be very helpful thank you.
Don't use ai to answer I will report you answer
Q1/ A three phase, 500 kVA, 6600 V, 50 Hz, 6 pole, star connected synchronous motor has synchronous
impedance of J 70 ohm per phase at its normal rating, the motor is excited to give unity power factor at the input
terminals. Find
a) The rated current and power factor.
b) The emf behind the synchronous impedance.
c) The developed torque.
d) The pull out torque.
e) The increase in excitation which will just permit an increase of 30% of rated torque before pulling out of
synchronism.
(45 M.)
Chapter 3 Solutions
Fundamentals of Electromagnetics with Engineering Applications
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