Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
7th Edition
ISBN: 9780072848236
Author: Warren McCabe, Julian C. Smith, Peter Harriott
Publisher: McGraw-Hill Companies, The
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Chapter 3, Problem 3.11P

(a)

Interpretation Introduction

Interpretation:

The type of flow at temperature 200°C is to be determined.

Concept Introduction :

Reynolds number is the ratio of inertia forces to the viscous forces. It is used to check the type of flow of fluids through pipe and tubes.

The formula of Reynolds number is,

  NRe=ρVDμ

As the temperature is increased from 100°Cto200°C , there will be a slight change in density of the fluid and velocity increases in same proportion.

The variation of viscosity with the temperature is given as:

  μ2μ1=( T 2 T 1 )0.65

(b)

Interpretation Introduction

Interpretation:

The type of flow on increasing tube size is to be determined.

Concept Introduction :

Reynolds number is the ratio of inertia forces to the viscous forces. It is used to check the type of flow of fluids through pipe and tubes.

The formula of Reynolds number is,

  NRe=ρVDμ

The diameter of the tube is inversely proportional to the square root of velocity.

The relationship between diameter and velocity is given as:

  D1D2=V2V1

By suing the above relationship, find out the velocity at increased diameter.

(c)

Interpretation Introduction

Interpretation:

The type of flow at increased pressure is to be determined.

Concept Introduction :

Reynolds number is the ratio of inertia forces to the viscous forces. It is used to check the type of flow of fluids through pipe and tubes.

The formula of Reynolds number is,

  NRe=ρVDμ

The density of the fluid is affected by the pressure.

The relationship between density and pressure is given as,

  ρ=PMRT

On increasing the pressure, the density also increases but the velocity decreases in the same proportion.

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(11.35. For a binary gas mixture described by Eqs. (3.37) and (11.58), prove that: 4812 Pу132 ✓ GE = 812 Py1 y2. ✓ SE dT HE-12 T L = = (812 - 7 1/8/123) d² 812 Pylyz C=-T Pylyz dT dT² See also Eq. (11.84), and note that 812 = 2B12 B11 - B22. perimental values of HE for binary liquid mixtures of
please provide me the solution with more details. because the previous solution is not clear
please, provide me the solution with details.
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Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:9780072848236
Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The