Connect for Chemistry
13th Edition
ISBN: 9781260161854
Author: Raymond Chang, Jason Overby
Publisher: Mcgraw-hill Higher Education (us)
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Chapter 3, Problem 3.117QP
Interpretation Introduction
Interpretation:
The greater mass of the given compound should be identified.
To find: The molar mass of chlorophyll.
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Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone
required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one
molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01
number of moles= 0.400/277.15 = 0.00144 moles
2 x 0.00 144=0.00288 moves
arams of acetophenone = 0.00144 X 120.16 = 0.1739
0.1739x2=0.3469
grams of benzaldehyde = 0.00144X106.12=0.1539
0.1539x2 = 0.3069
Starting materials:
0.3469 Ox acetophenone,
0.3069 of benzaldehyde
3
1.
Answer the questions about the following reaction:
(a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this
reaction. Be sure to include any relevant stereochemistry in the product structure.
+
SK
F
Br
+
(b) In which solvent would this reaction proceed the fastest (Circle one)
Methanol
Acetone
(c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the
one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you
observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest
other products that are formed? Draw them in the box provided.
3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants
or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure
and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in
the reactant before being able to draw the arrows corresponding to product formation.
A.
B.
Rearrangement
ΘΗ
Chapter 3 Solutions
Connect for Chemistry
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