Chapter 3, Problem 3.10E

Indentify and correct the errors in each of the following. [Note: There may be more than one error in each piece of code.]

Program Plan Intro

a. To identify and correct the error in the given codes.

Explanation of Solution

The error is in the first line of the code. The “if” statement shouldn’t end with a semicolon.

The correction involves the removal of the statement terminator (;) at the end of the first line of code because if there will be semicolon the puts statements won’t get executed.

The correct code will be −

if(age>=65)
puts("Age is greater than or equal to 65\n");
else
puts("Age is less than 65\n");

Program Plan Intro

b. To identify and correct the error in the given codes.

Explanation of Solution

There is as such no error with the syntax or logical of the given code segment.However, it is always recommended to initialize the variables with some initial values in order to avoid problem of garbage value. Therefore, the variable “total” should be initialized with 0.

The correct code

int x=1, total =0;
while(x<=10)
{
    total+=x;
++x;
}

Program Plan Intro

c. To identify and correct the error in the given codes.

Explanation of Solution

There are two errors in the given code.

The first correction involves the correction of name of the keyword while from “While” to “while”.

The second correction involves the enclosing the second and third statement withincurly braces.

So, the correct code will be as follows-

while(x<=100)
{
    total+=x;
++x;
}

Program Plan Intro

d. To identify and correct the error in the given codes.

Explanation of Solution

The given code has the error in the while statement. The given statement is an infinite loop because y will keep on increasing (provided base value of y is positive) and will always be greater than 0.

The above problem can be solved by decrementing the y-value instead of incrementing.

The correct code will be as follows-

while(y>0)
{
printf("%d\n",y);
--y;
}