(a) Interpretation: Empirical formula of benzene needs to be determined. Concept introduction: The simplest positive integer ratio of atoms of the chemical compound is called an empirical formula. From the empirical formula, the actual number of atoms present in the compound cannot be determined.
(a) Interpretation: Empirical formula of benzene needs to be determined. Concept introduction: The simplest positive integer ratio of atoms of the chemical compound is called an empirical formula. From the empirical formula, the actual number of atoms present in the compound cannot be determined.
Solution Summary: The author explains that the simplest positive integer ratio of atoms of the chemical compound is called an empirical formula.
Empirical formula of benzene needs to be determined.
Concept introduction:
The simplest positive integer ratio of atoms of the chemical compound is called an empirical formula. From the empirical formula, the actual number of atoms present in the compound cannot be determined.
Interpretation Introduction
(b)
Interpretation:
Molecular weight and its molecular formula from the mass spectrum of benzene needs to be determined.
Concept introduction:
The chemical symbol is used for constituent elements which are followed by the subscript describing the present number of atoms of each element in the molecule by using the molecular formula.
The value of empirical and molecular formula may be the same or a multiple of the compound empirical formula.
. A sample of 1.000 g of a compound containing carbon and hydrogen reacts with oxygen at elevated temperature to yield 0.692 g H2O and 3.381 g CO2.(a) Calculate the masses of C and H in the sample.(b) Does the compound contain any other elements?(c) What are the mass percentages of C and H in thecompound?(d) What is the empirical formula of the compound?
(c) An organic compound consists of carbon, hydrogen and sulfur only.The percentage of carbon by mass in this compound was found to be 30.27%.The complete combustion of 1.367 g this compound produces 1.765 g of sulfur dioxide(SO2)
(i) Determine the empirical formula for this compound.(ii) If a sample of this compound having the mass 3.781 × 103 mg contains 9.528 × 10–3 molesof the compound, determine the molecular formula.
3) An organic compound contains only C, H, and O. Complete combustion of a 3.185
g sample in an excess of oxygen yields 8.846 g CO2 and 2.507 g H2O.
(a) What is the percent composition, by mass, of this compound?
(b) What is the empirical formula of the compound?
(c) If the molar mass of this compound is 206 g/mol, what is the molecular formula?
(C: 12.01 g/mol; H: 1.01 g/mol; O: 16.0 g/mol)
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