Explanation The program is given below: // This program calculates the volume corresponding to //different structures based on users choice. //include headerfiles #include #include //include namespace Using namespace std: //main program begins here Int main() { //declare variables Int choice: Double a,b,calpha,beta,gama,volume: //display structures Court << “1,cubic/n2. Tetragonal/n3. Orthohombic/4.hexagonal/5. Rhombohedral or trigonal/n6. Monoclinic/n7. Triclinic/n”; //prompt user to input choice Court << “Enter choice”; //read choice Cin>>choice; //calculate volume based on user choice using switch Switch(choice) { //calculate volume of cubic structre Case 1: Court<< “Enter a”; Cin>>a Volume =pow(a,3,0); Court<< “The unit cell volume is “<<volume<< “A^3”<<end, Court<< “The unit cell volume is “<<volume<< “10^-3 nm^3” Step 3 //calculate volume of Tetragonal structure Case2; Court<< “Enter a:”, Cin>>a; Court<< “Enter c:”, Cin>>c; Volume = (pow(a,2,0))*c; Court << “The unit cell volume is “<<volume<< “A^3”<<endl; Court << “The unit cell volume is “<<volume<< “10^-3 nm^3”, Break; //calculate volume of orthorhombic structure Case3; Court<< “Enter a:”, Cin>>a; Court<< “Enter b:”, Cin>>b; Court<< “Enter c:”, Cin>>c; Volume =a* b* c Court << “The unit cell volume is “<<volume<< “A^3”<<endl; Court << “The unit cell volume is “<<volume<< “10^-3 nm^3”, Break; //calculate volume of hexagonal structure Case4; Court<< “Enter a:”, Cin>>a; Court<< “Enter c:”, Cin>>c; Volume = 0.866 * (pow(a,2,0))*c); Court << “The unit cell volume is “<<volume<< “A^3”<<endl; Court << “The unit cell volume is “<<volume<< “10^-3 nm^3”, Break; //calculate volume of rhombohedral structure Case5; Court<< “Enter a:”, Cin>>a; Court<< “Enter alpha:”, Cin>>alpha; Volume =((pow(a,3,0))*(pow((1-(3*(pow(cos(alpha,2.0)))+(2*(pow(cos(alha),2.0)))),0.5))); Court << “The unit cell volume is “<<volume<< “A^3”<<endl; Court << “The unit cell volume is “<<volume<< “10^-3 nm^3”, Break; //calculate volume of monoclinic structure Case6: Court<< “Enter a:”, Cin>>a; Court<< “Enter b:”, Cin>>b; Court<< “Enter c:”, Cin>>c; Court<< “Enter beta:”; Cin>>beta; Volume = (a*b*c)*(sin(beta)); Court << “The unit cell volume is “<<volume<< “A^3”<<endl; Court << “The unit cell volume is “<<volume<< “10^-3 nm^3”, Break; //calculate volume of triclinic structure Case7: Court<< “Enter a:”, Cin>>a; Court<< “Enter b:”, Cin>>b; Court<< “Enter c:”, Cin>>c; Court<< “Enter alpha:”, Cin>>alpha; Court<< “Enter beta:”; Cin>>beta; Court << “Enter gama:”, Cin>>gama; Volume = (a*b*c)*(pow(cos(alpha),2...

7th Edition

ISBN: 9780357447888

Author: ASKELAND

Publisher: CENGAGE L

See similar textbooks

Concept explainers

The Space Lattice and Unit Cells

Every matter consists of atoms, molecules, and ions. If these atoms, molecules, and ions (micro-particles) are represented in a three-dimensional space-occupying certain specific points in space, then these arrangements are termed as space lattices and t…

Question

Chapter 3, Problem 3.103CP

To determine

The program for the volume of different types of the unit cells.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 3, Problem 3.102DP

Chapter 3, Problem 3.104CP

Students have asked these similar questions

Calculate the vertical cross section moment of inertia for Orientations 1 and 2. State which number is the higher moment of inertia using equation 1. Given: b1=1 in, h1=1.5 in, b2=1.5 in, h2=1 in, t=0.0625 in. Then calculate the maximum deflection for a point load of 8 lb on the free end of the beam using equation 2. Given: E=10.1*10^6 psi. 1. ((bh^3)/12) - (((b-2t)(h-2t)^3))/12) 2. S = (PL^3)/(3EI)

1-69E The pressure in a natural gas pipeline is measured by the manometer shown in Fig. P1-69E with one of the arms open to the atmosphere where the local atmospheric pressure is 14.2 psia. Determine the absolute pressure in the pipeline. Natural Gas 10 in 6 in FIGURE P1-69E Mercury SG= 13.6 Air 2 in + 25 in Water

B 150 mm 120 mm PROBLEM 15.193 The L-shaped arm BCD rotates about the z axis with a constant angular velocity @₁ of 5 rad/s. Knowing that the 150-mm- radius disk rotates about BC with a constant angular velocity @2 of 4 rad/s, determine (a) the velocity of Point A, (b) the acceleration of Point A. Answers: V₁ =-(0.600 m/s)i + (0.750 m/s)j - (0.600 m/s)k a=-(6.15 m/s²)i- (3.00 m/s²)j

Chapter 3 Solutions

SCIENCE+ENGR.OF MTRLS.,SI ED.,ENHANCED

Ch. 3 - Prob. 3.1P Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - What is a polycrystalline material?Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.9P Ch. 3 - Prob. 3.10P

Ch. 3 - Prob. 3.11P Ch. 3 - Prob. 3.12P Ch. 3 - Prob. 3.13P Ch. 3 - Prob. 3.14P Ch. 3 - Prob. 3.15P Ch. 3 - Prob. 3.16P Ch. 3 - Prob. 3.17P Ch. 3 - Prob. 3.18P Ch. 3 - Prob. 3.19P Ch. 3 - Prob. 3.20P Ch. 3 - Prob. 3.21P Ch. 3 - Prob. 3.22P Ch. 3 - Prob. 3.23P Ch. 3 - Prob. 3.24P Ch. 3 - Prob. 3.25P Ch. 3 - Aluminum foil used to package food isapproximately...Ch. 3 - Prob. 3.27P Ch. 3 - Prob. 3.28P Ch. 3 - Thoria or thonrium dioxide can be describedas an...Ch. 3 - Prob. 3.30P Ch. 3 - Prob. 3.31P Ch. 3 - Prob. 3.32P Ch. 3 - Prob. 3.33P Ch. 3 - Prob. 3.34P Ch. 3 - Prob. 3.35P Ch. 3 - Prob. 3.36P Ch. 3 - Prob. 3.37P Ch. 3 - Prob. 3.38P Ch. 3 - Prob. 3.39P Ch. 3 - Prob. 3.40P Ch. 3 - Prob. 3.41P Ch. 3 - Prob. 3.42P Ch. 3 - Prob. 3.43P Ch. 3 - Prob. 3.44P Ch. 3 - Prob. 3.45P Ch. 3 - Prob. 3.46P Ch. 3 - Prob. 3.47P Ch. 3 - Prob. 3.48P Ch. 3 - Prob. 3.49P Ch. 3 - Prob. 3.50P Ch. 3 - Prob. 3.51P Ch. 3 - Prob. 3.52P Ch. 3 - Prob. 3.53P Ch. 3 - Prob. 3.54P Ch. 3 - Prob. 3.55P Ch. 3 - Prob. 3.56P Ch. 3 - Prob. 3.57P Ch. 3 - Prob. 3.58P Ch. 3 - Prob. 3.59P Ch. 3 - Prob. 3.60P Ch. 3 - Prob. 3.61P Ch. 3 - Prob. 3.62P Ch. 3 - Prob. 3.63P Ch. 3 - Prob. 3.64P Ch. 3 - Prob. 3.65P Ch. 3 - Prob. 3.66P Ch. 3 - Prob. 3.67P Ch. 3 - Prob. 3.68P Ch. 3 - Prob. 3.69P Ch. 3 - Prob. 3.70P Ch. 3 - Prob. 3.71P Ch. 3 - Prob. 3.72P Ch. 3 - Prob. 3.73P Ch. 3 - Prob. 3.74P Ch. 3 - Prob. 3.75P Ch. 3 - Prob. 3.76P Ch. 3 - Determine the planar density and packing fraction...Ch. 3 - Prob. 3.78P Ch. 3 - Prob. 3.79P Ch. 3 - Prob. 3.80P Ch. 3 - Prob. 3.81P Ch. 3 - Prob. 3.82P Ch. 3 - Prob. 3.83P Ch. 3 - Prob. 3.84P Ch. 3 - Prob. 3.85P Ch. 3 - Prob. 3.86P Ch. 3 - Prob. 3.87P Ch. 3 - Prob. 3.88P Ch. 3 - Prob. 3.89P Ch. 3 - Prob. 3.90P Ch. 3 - Prob. 3.91P Ch. 3 - MgO, which has the sodium chloride structure, has...Ch. 3 - Prob. 3.93P Ch. 3 - Prob. 3.94P Ch. 3 - Prob. 3.95P Ch. 3 - Prob. 3.96P Ch. 3 - Prob. 3.97P Ch. 3 - Prob. 3.98P Ch. 3 - Prob. 3.99P Ch. 3 - Prob. 3.100P Ch. 3 - Prob. 3.101DP Ch. 3 - You want to design a material for making kitchen...Ch. 3 - Prob. 3.103CP Ch. 3 - Prob. 3.104CP Ch. 3 - Prob. 3.1KP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The program for the volume of different types of the unit cells.

Solution Summary: The author describes the program for the volume of different types of unit cells.

Concept explainers

The program for the volume of different types of the unit cells.

Want to see the full answer?

Chapter 3 Solutions