Starting Out with Programming Logic and Design (4th Edition)
4th Edition
ISBN: 9780133985078
Author: Tony Gaddis
Publisher: PEARSON
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Question
Chapter 3, Problem 2MC
The code reuse reduces the duplication of code.
Hence, the correct answer is option “A”.
Program Plan Intro
Module:
- A module is a group of statement that is present in a program in order to perform specific tasks.
- Module is used to reduce complexity of a program. Instead of writing a large complex program, it can be divided into small chunks, each one performing particular part of the task.
- The approach of dividing a program into smaller chunks is called as “divide and conquer” because; a large program is divided into smaller tasks that can be easily performed.
- Module is also called as function.
- Single program contains more than one module.
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Students have asked these similar questions
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
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1. Default forwarded
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map the following ER diagram into a relational database schema diagram. you should take into account all the constraints in the ER diagram. Underline the primary key of each relation, and show each foreign key as a directed arrow from the referencing attributes (s) to the referenced relation.
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Chapter 3 Solutions
Starting Out with Programming Logic and Design (4th Edition)
Ch. 3.1 - What is a module?Ch. 3.1 - Prob. 3.2CPCh. 3.1 - Prob. 3.3CPCh. 3.1 - Prob. 3.4CPCh. 3.1 - Prob. 3.5CPCh. 3.2 - In most languages, a module definition has what...Ch. 3.2 - Prob. 3.7CPCh. 3.2 - Prob. 3.8CPCh. 3.2 - Prob. 3.9CPCh. 3.3 - What is a local variable? How is access to a local...
Ch. 3.3 - What is a variables scope?Ch. 3.3 - Prob. 3.12CPCh. 3.3 - Prob. 3.13CPCh. 3.4 - Prob. 3.14CPCh. 3.4 - What are the variables that receive pieces of data...Ch. 3.4 - Prob. 3.16CPCh. 3.4 - Prob. 3.17CPCh. 3.4 - Prob. 3.18CPCh. 3.5 - What is the scope of a global variable?Ch. 3.5 - Give one good reason that you should not use...Ch. 3.5 - Prob. 3.21CPCh. 3 - A group of statements that exist within a program...Ch. 3 - Prob. 2MCCh. 3 - The first line of a module definition is known as...Ch. 3 - Prob. 4MCCh. 3 - Prob. 5MCCh. 3 - A design technique that programmers use to break...Ch. 3 - Prob. 7MCCh. 3 - A _____ is a variable that is declared inside a...Ch. 3 - A(n) ____ is the part of a program in which a...Ch. 3 - A(n) ____ is a piece of data that is sent into a...Ch. 3 - A(n) ____ is a special variable that receives a...Ch. 3 - When _____, only a copy of the argument's value is...Ch. 3 - When ____, the module can modify the argument in...Ch. 3 - A variable that is visible to every module in the...Ch. 3 - When possible, you should avoid using _____...Ch. 3 - The phrase divide and conquer means that all of...Ch. 3 - Prob. 2TFCh. 3 - Module names should be as short as possible.Ch. 3 - Prob. 4TFCh. 3 - A flowchart shows the hierarchical relationships...Ch. 3 - Prob. 6TFCh. 3 - A statement in one module can access a local...Ch. 3 - In most programming languages, you cannot have two...Ch. 3 - Programming languages typically require that...Ch. 3 - Most languages do not allow you to write modules...Ch. 3 - When an argument is passed by reference, the...Ch. 3 - Prob. 12TFCh. 3 - Prob. 1SACh. 3 - Prob. 2SACh. 3 - Prob. 3SACh. 3 - What is a local variable? What statements are able...Ch. 3 - In most languages, where does a local variables...Ch. 3 - What is the difference between passing an argument...Ch. 3 - Prob. 7SACh. 3 - Design a module named timesTen. The module should...Ch. 3 - Examine the following pseudocode module header,...Ch. 3 - Look at the following pseudocode module header:...Ch. 3 - Assume that a pseudocode program contains the...Ch. 3 - Design a module named getNumber, which uses a...Ch. 3 - What will the following pseudocode program...Ch. 3 - What will the following pseudocode program...Ch. 3 - Find the error in the following pseudocode. Module...Ch. 3 - Find the error in the following pseudocode. Module...Ch. 3 - Find the potential error in the following...Ch. 3 - Prob. 4DECh. 3 - Kilometer Converter Design a modular program that...Ch. 3 - Prob. 2PECh. 3 - How Much Insurance? Many financial experts advise...Ch. 3 - Prob. 4PECh. 3 - Prob. 5PECh. 3 - Prob. 6PECh. 3 - Calories from Fat and Carbohydrates A nutritionist...Ch. 3 - Prob. 8PECh. 3 - Prob. 9PECh. 3 - Monthly Sales Tax A retail company must file a...Ch. 3 - Prob. 11PE
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- What is business intelligence? Share the Business intelligence (BI) tools you have used and explain what types of decisions you made.arrow_forwardI need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place. My code: % Define frequency range for the plot f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz w = 2 * pi * f; % Angular frequency % Parameters for the filters - let's adjust these to get more reasonable cutoffs R = 1e3; % Resistance in ohms (1 kΩ) C = 1e-6; % Capacitance in farads (1 μF) % For bandpass, we need appropriate L value for desired cutoffs L = 0.1; % Inductance in henries - adjusted for better bandpass response % Calculate cutoff frequencies first to verify they're in desired range f_cutoff_RC = 1 / (2 * pi * R * C); f_resonance = 1 / (2 * pi * sqrt(L * C)); Q_factor = (1/R) * sqrt(L/C); f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor)); f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor)); % Transfer functions % Low-pass filter (RC) H_low = 1 ./ (1 + 1i * w *…arrow_forwardTask 3. i) Compare your results from Tasks 1 and 2. j) Repeat Tasks 1 and 2 for 500 and 5,000 elements. k) Summarize run-time results in the following table: Time/size n String StringBuilder 50 500 5,000arrow_forward
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